Question

我正在做我的Bsc IT主要项目，我正在做电影票务系统我有3张桌子

影

   movieID   movieName  ticketPrice
    1001       3 idiots     200
    1002       ready    300
    1003       robot    250

时间表

showId   movieId
9001     1001
9002     1003
9003     1002

票

ticketNo  showId   soldBy  
21        9001     A
73        9001     B
23        9001     A
22        9001     A
64        9002     A
34        9003     B
11        9001     A
98        9001     A
38        9003     B
78        9001     B
24        9002     A
31        9001     A

我想得到以下结果

userName  showId  TotalAmount(Product of Count(TicketNo) and ticketPrice)
A         9001    1200
A         9002    500
B         9001    400
B         9003    600

请帮帮我

Answer 1

SELECT
  t.soldBy AS userName,
  t.showId,
  SUM(m.ticktPrice) AS TotalAmount
FROM
  tickets t
  INNER JOIN schedule s ON s.showId = t.showId
  INNER JOIN movies m ON m.movieId = s.movieId
GROUP BY
  t.soldBy,
  t.showId

Answer 2

select t.soldBy userName, t.showId showId, count(t.ticketNo) * m.tickeprice total
from tickets t
inner join schedule s on t.showId = s.showId
inner join movies m on m.movieId = s.movieId
group by t.soldBy, t.showId

Answer 3

SELECT 
  T.`soldBy`,
  T.`showId`,
  SUM(M.`ticketPrice`) 
FROM
  tickets AS T 
  INNER JOIN schedule AS S 
    ON T.`showId` = S.`showId` 
  INNER JOIN movies AS M 
    ON S.`movieID` = M.`movieID` 
GROUP BY T.`soldBy`,
  T.`showId` ;

只是一个想法：在许多地方习惯于在电影院中有不同的价格，不仅因为电影，而且因为电影播放的时间（即早晨更便宜，周末晚上更贵）。如果你想考虑到这一点，那么你不应该将价格与电影联系起来，而应该与节目相关联。

结果表中的SQL帮助

3 个答案: