Question

到目前为止，我有代码

- (void)CreatenewBlock:(int)blockCountToSpawn
{
    for (int i=0; i != blockCountToSpawn; i++) 
    {
        theBlockxCord = arc4random() % 4;
        theBlockyCord = arc4random() % 4;
        NSLog(@"New Block with Cords (%i, %i)",theBlockxCord, theBlockyCord);
    }

}

循环直到达到blockCountToSpawn的数量这正是我想要的方式，但我想每次都将theBlockxCord设置为一个新变量。所以最终结果将是：

theBlockxCordOfBlock1=2
theBlockxCordOfBlock2=4
theBlockxCordOfBlock3=1
theBlockxCordOfBlock4=3

而不是每次都覆盖BlockXCord。

对于奖励积分，有没有一种方法可以在阵列中调用它们，所以我不必继续这样做：

if (theBlockxCordOfBlock1 == 2 || theBlockxCordOfBlock3 == 2 ..etc)
{
   do stuff..
}

Answer 1

您可以使用C数组或NSMutableArray。在将int添加到数组之前，您必须将NSNumber转换为- (void)CreatenewBlock:(int)blockCountToSpawn { NSMutableArray *blockXCoord = [NSMutableArray array]; // Retain it as needed. NSMutableArray *blockYCoord = [NSMutableArray array]; for (int i=0; i != blockCountToSpawn; i++) { [blockXCoord addObject:[NSNumber numberWithInt:(arc4random() % 4)]; [blockYCoord addObject:[NSNumber numberWithInt:(arc4random() % 4)]; } ... }。

如果您要搜索if ( [blockXCoord indexOfObject:[NSNumber numberWithInt:2]] != NSNotFound ) { ... do stuff }，请执行此操作

if ( [blockXCoord containsObject:[NSNumber numberWithInt:2]] ) {
    ... do stuff
}

或

for ( int i = 0; i < [blockXCoord count]; i++ ) {
    NSPoint point = NSMakePoint([[blockXCoord objectAtIndex:i] intValue],[[blockYCoord objectAtIndex:i] intValue]);

    ... do something with the point.
}

修改

{{1}}

Answer 2

对于您的第一个问题：将结果放入常规数组中，就像任何C程序或NSMutableArray一样。 http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSMutableArray_Class/Reference/Reference.html

对于第二个问题：如果使用NSMutableArray存储对象（例如，NSNumber），则可以调用containsObject:来确定对象是否在数组中。 http://developer.apple.com/library/ios/documentation/cocoa/reference/foundation/Classes/NSArray_Class/NSArray.html#//apple_ref/occ/instm/NSArray/containsObject：

将int赋值给new int

2 个答案: