Question

我有两个功能。他们实际上在做同样的事情。通过fieldNameArray从数据库结果中获取数据到Int或Double数组中。如何将这两个函数合并为一个？那可能吗？唯一的区别是字段类型，所以返回类型。

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Answer 1

您可以尝试泛型，例如

func fieldsToNumber<T> ( fieldNameArray : [String] ) -> [T] {
   var returnArray = [T]()
   for fNA in fieldNameArray {
   let n = T ( results.int(forColumn: fNA) )
      returnArray.append( n )
   }
   return returnArray;
}

Answer 2

是的，有可能应该使用Generics，尤其是您需要通用函数。

解决您问题的代码大致如下：

#!/usr/bin/env python
"""
Given a list of triangles, find the connected components.

https://stackoverflow.com/q/61584283/2912349
"""
import itertools
import networkx as nx

faces = [[ 2,  1,  0],  [ 0,  3,  2],  [ 1,  4,  0],  [ 0,  4,  3],  [ 5,  1,  2],  [ 3,  5,  2],
         [ 5,  4,  1],  [ 4,  5,  3],  [ 8,  7,  6],  [ 6,  9,  8],  [ 7, 10,  6],  [ 6, 10,  9],
         [11,  7,  8],  [ 9, 11,  8],  [11, 10,  7],  [10, 11,  9]]

#create graph
edges = []
for face in faces:
    edges.extend(list(itertools.combinations(face, 2)))
g = nx.from_edgelist(edges)

# compute connected components and print results
components = list(nx.algorithms.components.connected_components(g))

for component in components:
    print(component)

# {0, 1, 2, 3, 4, 5}
# {6, 7, 8, 9, 10, 11}

# separate faces by component
component_to_faces = dict()
for component in components:
    component_to_faces[tuple(component)] = [face for face in faces if set(face) <= component] # <= operator tests for subset relation

for component, component_faces in component_to_faces.items():
    print(component, component_faces)
# (0, 1, 2, 3, 4, 5) [[2, 1, 0], [0, 3, 2], [1, 4, 0], [0, 4, 3], [5, 1, 2], [3, 5, 2], [5, 4, 1], [4, 5, 3]]
# (6, 7, 8, 9, 10, 11) [[8, 7, 6], [6, 9, 8], [7, 10, 6], [6, 10, 9], [11, 7, 8], [9, 11, 8], [11, 10, 7], [10, 11, 9]]

请用函数// This is a struct to mock the code you didn't post struct Results { func int(forColumn: String) -> Int16 { return 1 } } let results = Results() protocol DatabaseElementRepresentable { init?(_ databaseValue: Int16) } func fields<Element: DatabaseElementRepresentable>(fieldNameArray : [String]) -> [Element] { var returnArray = [Element]() for fNA in fieldNameArray { if let n = Element(results.int(forColumn: fNA)) { returnArray.append(n) } } return returnArray } extension Int: DatabaseElementRepresentable { } extension Double: DatabaseElementRepresentable { } let ints: [Int] = fields(fieldNameArray: ["test"]) let doubles: [Double] = fields(fieldNameArray: ["test"])返回的值更改Int16

将两个几乎相同的功能合而为一？

2 个答案: