Question

我有一个文件名数组。这些中的一部分可能具有类似这样的模式（字母串在末尾带有数字）：

arr = %w[
  WordWord1.html
  WordWord3.html
  WordWord10.html
  WordWord11.html
  AnotherWord1.html
  AnotherWord2.html
  FileFile.html
]

如何识别相似的子串（它们具有相同的子串，只是它们的数字不同）并将它们移动到数组中？

['WordWord1.html', 'WordWord3.html', 'WordWord10.html', 'WordWord11.html']
['AnotherWord1.html', 'AnotherWord2.html']
['FileFile.html']

Answer 1

arr.group_by { |x| x[/[a-zA-Z]+/] }.values

Answer 2

filenames = ["WordWord1.html", "WordWord3.html", "WordWord10.html", "WordWord11.html", "AnotherWord1.html", "AnotherWord2.html", "FileFile.html"]
filenames.inject({}){|h,f|k = f.split(/[^a-zA-Z]/, 2).first;h[k] ||= [];h[k] << f; h}

Answer 3

arr = %w[
  WordWord1.html
  WordWord3.html
  WordWord10.html
  WordWord11.html
  AnotherWord1.html
  AnotherWord2.html
  FileFile.html
]

result = {}

arr.each do |a|
  prefix = a.match(/[A-Za-z]+/).to_s
  if result[prefix]
    result[prefix] << a
  else
    result[prefix] = [a]
  end
end

p result

在Ruby中将类似模式的字符串分组

3 个答案: