我正在编写一个函数来获取速记值并将它们转换为标准化的数字格式。是否有任何标准代码可以对任意测量文本进行“最佳”转换，如果文本有效则将其转换为数字测量值？
我想我正在寻找像bool TryParseMeasurement（string s，out decimal d）之类的东西。有谁知道这样的功能？
以下是我见过的一些输入值的示例：
帝国
Metricc
答案 0 :(得分：6)
这是我们在很久以前在应用程序中编写的一些代码，我们在这里做了类似的事情。这不是最好的，但你可以适应，或者获得某种跳跃点。
public static class UnitConversion
{
public static string[] lstFootUnits = new string[] {"foots", "foot", "feets", "feet", "ft", "f", "\""};
public static string sFootUnit = "ft";
public static string[] lstInchUnits = new string[] { "inches", "inchs", "inch", "in", "i", "\'" };
public static string sInchUnit = "in";
public static string[] lstPoundUnits = new string[] { "pounds", "pound", "pnds", "pnd", "lbs", "lb", "l", "p" };
public static string sPoundUnit = "lbs";
public static string[] lstOunceUnits = new string[] { "ounces", "ounce", "ozs", "oz", "o" };
public static string sOunceUnit = "oz";
public static string[] lstCentimeterUnits = new string[] { "centimeters", "centimeter", "centimetres", "centimetre", "cms", "cm", "c"};
public static string sCentimeterUnit = "cm";
public static string[] lstKilogramUnits = new string[] { "kilograms", "kilogram", "kilos", "kilo", "kgs", "kg", "k" };
public static string sKilogramsUnit = "kgs";
/// <summary>
/// Attempt to convert between feet/inches and cm
/// </summary>
/// <param name="sHeight"></param>
/// <returns></returns>
public static string ConvertHeight(string sHeight)
{
if (!String.IsNullOrEmpty(sHeight))
{
sHeight = UnitConversion.CleanHeight(sHeight);
if (sHeight.Contains(UnitConversion.sFootUnit))
{
sHeight = sHeight.Replace(UnitConversion.sFootUnit, "|");
sHeight = sHeight.Replace(UnitConversion.sInchUnit, "|");
string[] sParts = sHeight.Split('|');
double? dFeet = null;
double? dInches = null;
double dFeetParsed;
double dInchesParsed;
if (sParts.Length >= 2 && double.TryParse(sParts[0].Trim(), out dFeetParsed))
{
dFeet = dFeetParsed;
}
if (sParts.Length >= 4 && double.TryParse(sParts[2].Trim(), out dInchesParsed))
{
dInches = dInchesParsed;
};
sHeight = UnitConversion.FtToCm(UnitConversion.CalculateFt(dFeet ?? 0, dInches ?? 0)).ToString() + " " + UnitConversion.sCentimeterUnit;
}
else if (sHeight.Contains(UnitConversion.sCentimeterUnit))
{
sHeight = sHeight.Replace(UnitConversion.sCentimeterUnit, "|");
string[] sParts = sHeight.Split('|');
double? dCentimeters = null;
double dCentimetersParsed;
if (sParts.Length >= 2 && double.TryParse(sParts[0].Trim(), out dCentimetersParsed))
{
dCentimeters = dCentimetersParsed;
}
int? iFeet;
int? iInches;
if (UnitConversion.CmToFt(dCentimeters, out iFeet, out iInches))
{
sHeight = (iFeet != null) ? iFeet.ToString() + " " + UnitConversion.sFootUnit : "";
sHeight += (iInches != null) ? " " + iInches.ToString() + " " + UnitConversion.sInchUnit : "";
sHeight = sHeight.Trim();
}
else
{
sHeight = "";
}
}
else
{
sHeight = "";
}
}
else
{
sHeight = "";
}
return sHeight;
}
/// <summary>
/// Attempt to convert between Kgs and Lbs
/// </summary>
/// <param name="sWeight"></param>
/// <returns></returns>
public static string ConvertWeight(string sWeight)
{
if (!String.IsNullOrEmpty(sWeight))
{
sWeight = UnitConversion.CleanWeight(sWeight);
if (sWeight.Contains(UnitConversion.sKilogramsUnit))
{
sWeight = sWeight.Replace(UnitConversion.sKilogramsUnit, "|");
string[] sParts = sWeight.Split('|');
double? dKilograms = null;
double dKilogramsParsed;
if (sParts.Length >= 2 && double.TryParse(sParts[0].Trim(), out dKilogramsParsed))
{
dKilograms = dKilogramsParsed;
}
sWeight = UnitConversion.KgToLbs(dKilograms).ToString("#.###") + " " + UnitConversion.sPoundUnit;
}
else if (sWeight.Contains(UnitConversion.sPoundUnit))
{
sWeight = sWeight.Replace(UnitConversion.sPoundUnit, "|");
string[] sParts = sWeight.Split('|');
double? dPounds = null;
double dPoundsParsed;
if (sParts.Length >= 2 && double.TryParse(sParts[0].Trim(), out dPoundsParsed))
{
dPounds = dPoundsParsed;
}
sWeight = UnitConversion.LbsToKg(dPounds).ToString("#.###") + " " + UnitConversion.sKilogramsUnit;
}
else
{
sWeight = "";
}
}
else
{
sWeight = "";
}
return sWeight;
}
public static double? CalculateFt(double dFt, double dInch)
{
double? dFeet = null;
if (dFt >= 0 && dInch >= 0 && dInch <= 12)
{
dFeet = dFt + (dInch / 12);
}
return dFeet;
}
public static double KgToLbs(double? dKg)
{
if (dKg == null)
{
return 0;
}
return dKg.Value * 2.20462262;
}
public static double LbsToKg(double? dLbs)
{
if (dLbs == null)
{
return 0;
}
return dLbs.Value / 2.20462262;
}
public static double FtToCm(double? dFt)
{
if (dFt == null)
{
return 0;
}
return dFt.Value * 30.48;
}
public static bool CmToFt(double? dCm, out int? iFt, out int? iInch)
{
if (dCm == null)
{
iFt = null;
iInch = null;
return false;
}
double dCalcFeet = dCm.Value / 30.48;
double dCalcInches = dCalcFeet - Math.Floor(dCalcFeet);
dCalcFeet = Math.Floor(dCalcFeet);
dCalcInches = dCalcInches * 12;
iFt = (int)dCalcFeet;
iInch = (int)dCalcInches;
return true;
}
private static string CleanUnit(string sOriginal, string[] lstReplaceUnits, string sReplaceWithUnit)
{
System.Text.StringBuilder sbPattern = new System.Text.StringBuilder();
foreach (string sReplace in lstReplaceUnits)
{
if (sbPattern.Length > 0)
{
sbPattern.Append("|");
}
sbPattern.Append(sReplace);
}
sbPattern.Insert(0,@"(^|\s)(");
sbPattern.Append(@")(\s|$)");
System.Text.RegularExpressions.Regex rReplace = new System.Text.RegularExpressions.Regex(sbPattern.ToString(), System.Text.RegularExpressions.RegexOptions.IgnoreCase);
sOriginal = rReplace.Replace(sOriginal, sReplaceWithUnit);
/*foreach (string sReplace in lstReplaceUnits)
{
sOriginal = sOriginal.Replace(sReplace, " " + sReplaceWithUnit);
}*/
return sOriginal;
}
private static bool StringHasNumbers(string sText)
{
System.Text.RegularExpressions.Regex rxNumbers = new System.Text.RegularExpressions.Regex("[0-9]+");
return rxNumbers.IsMatch(sText);
}
private static string ReduceSpaces(string sText)
{
while (sText.Contains(" "))
{
sText = sText.Replace(" ", " ");
}
return sText;
}
private static string SeperateNumbers(string sText)
{
bool bNumber = false;
if (!String.IsNullOrEmpty(sText))
{
for (int iChar = 0; iChar < sText.Length; iChar++)
{
bool bIsNumber = (sText[iChar] >= '0' && sText[iChar] <= '9') ||
(sText[iChar] == '.' && iChar < sText.Length - 1 && sText[iChar + 1] >= '0' && sText[iChar + 1] <= '9');
if (iChar > 0 && bIsNumber != bNumber)
{
sText = sText.Insert(iChar, " ");
iChar++;
}
bNumber = bIsNumber;
}
}
return sText;
}
public static string CleanHeight(string sHeight)
{
if (UnitConversion.StringHasNumbers(sHeight))
{
sHeight = SeperateNumbers(sHeight);
sHeight = CleanUnit(sHeight, UnitConversion.lstFootUnits, UnitConversion.sFootUnit);
sHeight = CleanUnit(sHeight, UnitConversion.lstInchUnits, UnitConversion.sInchUnit);
sHeight = CleanUnit(sHeight, UnitConversion.lstCentimeterUnits, UnitConversion.sCentimeterUnit);
sHeight = SeperateNumbers(sHeight);
sHeight = ReduceSpaces(sHeight);
}
else
{
sHeight = "";
}
return sHeight;
}
public static string CleanWeight(string sWeight)
{
if (UnitConversion.StringHasNumbers(sWeight))
{
sWeight = SeperateNumbers(sWeight);
sWeight = CleanUnit(sWeight, UnitConversion.lstOunceUnits, UnitConversion.sOunceUnit);
sWeight = CleanUnit(sWeight, UnitConversion.lstPoundUnits, UnitConversion.sPoundUnit);
sWeight = CleanUnit(sWeight, UnitConversion.lstKilogramUnits, UnitConversion.sKilogramsUnit);
sWeight = SeperateNumbers(sWeight);
sWeight = ReduceSpaces(sWeight);
}
else
{
sWeight = "";
}
return sWeight;
}
}
答案 1 :(得分：3)
为此目的，为您构建字符串的扩展方法应该很有用。构建扩展方法时，将新函数调用附加到现有类。在这里，我们将一个方法附加到'string'类，该类返回一个double，作为给定英制值中的毫米数，提示可以根据您提供的示例解析该值。
using System;
using System.Text;
namespace SO_Console_test
{
static class ConversionStringExtensions
{
//this is going to be a simple example you can
//fancy it up a lot...
public static double ImperialToMetric(this string val)
{
/*
* With these inputst we want to total inches.
* to do this we want to standardize the feet designator to 'f'
* and remove the inch designator altogether.
6 inches
6in
6”
4 feet 2 inches
4’2”
4 ‘ 2 “
3 feet
3’
3 ‘
3ft
3ft10in
3ft 13in (should convert to 4’1”) ...no, should convert to 49 inches, then to metric.
*/
//make the input lower case and remove blanks:
val = val.ToLower().Replace(" ", string.Empty);
//make all of the 'normal' feet designators to "ft"
string S = val.Replace("\'", "f").Replace("feet", "f").Replace("ft", "f").Replace("foot", "f").Replace("‘", "f").Replace("’", "f");
//and remove any inch designator
S = S.Replace("\"", string.Empty).Replace("inches", string.Empty).Replace("inch", string.Empty).Replace("in", string.Empty).Replace("“", string.Empty).Replace("”", string.Empty);
//finally we have to be certain we have a number of feet, even if that number is zero
S = S.IndexOf('f') > 0 ? S : "0f" + S;
//now, any of the inputs above will have been converted to a string
//that looks like 4 feet 2 inches => 4f2
string[] values = S.Split('f');
int inches = 0;
//as long as this produces one or two values we are 'on track'
if (values.Length < 3)
{
for (int i = 0; i < values.Length; i++)
{
inches += values[i] != null && values[i] != string.Empty ? int.Parse(values[i]) * (i == 0 ? 12 : 1) : 0 ;
}
}
//now inches = total number of inches in the input string.
double result = inches * 25.4;
return result;
}
}
}
使用它“ImperialToMetric（）”成为任何字符串的方法，并且可以在引用包含类ConversionStringExtensions的扩展名的任何地方调用它。您可以像使用它一样使用它：
namespace SO_Console_test
{
class Program
{
static void Main(string[] args)
{
showConversion();
Console.ReadLine();
}
private static void showConversion()
{
//simple start:
Console.WriteLine("6ft 2\"".ImperialToMetric().ToString() + " mm");
//more robust:
var Imperials = new List<string>(){"6 inches",
"6in",
"6”",
"4 feet 2 inches",
"4’2”",
"4 ‘ 2 “",
"3 feet",
"3’",
"3 ‘",
"3ft",
"3ft10in",
"3ft 13in"};
foreach (string imperial in Imperials)
{
Console.WriteLine(imperial + " converted to " + imperial.ImperialToMetric() + " millimeters");
}
}
}
显然，此时对"Fred".ImperialToMetric的调用不会很好。您将需要进行错误处理以及可能需要一些选项来转动1234 mm 1.234 km等等。但是一旦您将其冲洗出来，您就可以使用一种方法来选择。
答案 2 :(得分：1)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication5
{
class Program
{
static void Main(string[] args)
{
double km,m,f,i,cm;
Console.WriteLine("The distance between karachi and lahore in (kilometer)km is=");
km = Convert.ToInt32(Console.ReadLine());
m = km * 1000;
Console.WriteLine("The distance between karachi and lahore in meter(m) is="+m);
f = km * 3280.84;
Console.WriteLine("The distance between karachi and lahore in feet(f) is="+f);
i = km * 39370.1;
Console.WriteLine("The distance between karachi and lahore in inches(i) is="+i);
cm = m * 100;
Console.WriteLine("The distance between karachi and lahore in centimeter(cm) is="+cm);
Console.ReadLine();
}
}
}
答案 3 :(得分：0)
我写的一个字符串扩展名只是为了发现这里已经有一个解决方案:) 剩下要做的唯一一件事就是将“英尺”、“英尺”、“'”替换为“'”和“英寸” , "inch", "in", "", "\"" 到 "''"。
using System;
namespace CustomExtensions
{
public static class StringExtension
{
const float mPerFeet = 30.48f / 100;
const float mPerInch = 2.54f / 100;
// input options:
// 5'
// 5'6''
// 18''
// 24''
// 5'6
// 5 ' 6 ''
// 5' 6''
// corner cases:
// '' will return 0
// 5''6'' will interpret as 5'6''
// 5'6' will interpret as 5'6''
// 6 will interpret as 6''
// 6''' will interpret as 6''
public static float MetersFromFeetInches(this string feetInches)
{
float feet = 0;
float inches = 0;
string[] separators = new string[] { "'", "''", " " };
string[] subs = feetInches.Split(separators, StringSplitOptions.RemoveEmptyEntries);
if (subs.Length == 1)
{
if (feetInches.Trim().EndsWith("''"))
{
float.TryParse(subs[0], out inches);
}
else if (!feetInches.Trim().EndsWith("''") && !feetInches.Trim().EndsWith("'"))
{
float.TryParse(subs[0], out inches);
}
else
{
float.TryParse(subs[0], out feet);
}
}
else if (subs.Length > 1)
{
float.TryParse(subs[0], out feet);
float.TryParse(subs[1], out inches);
}
return feet * mPerFeet + inches * mPerInch;
}
}
}