我有以下 C 代码的一部分,它使用来自文件名WMM.COF的数据,并使用存储在文件中的数据来计算地球的磁场。程序运行正常,但我不能让程序访问外部文件;我想将所有数据都存储在程序中。我尝试使用结构数组来复制数据,然后将数组放入一个字符串,但这会导致程序出错并且不会产生正确的结果。这是我正在尝试修改的程序代码。
static void E0000(int IENTRY, int *maxdeg, double alt, double glat, double glon, double time, double *dec, double *dip, double *ti, double *gv)
{
static int maxord,i,icomp,n,m,j,D1,D2,D3,D4;
static double c[13][13],cd[13][13],tc[13][13],dp[13][13],snorm[169],
sp[13],cp[13],fn[13],fm[13],pp[13],k[13][13],pi,dtr,a,b,re,
a2,b2,c2,a4,b4,c4,epoch,gnm,hnm,dgnm,dhnm,flnmj,otime,oalt,
olat,olon,dt,rlon,rlat,srlon,srlat,crlon,crlat,srlat2,
crlat2,q,q1,q2,ct,st,r2,r,d,ca,sa,aor,ar,br,bt,bp,bpp,
par,temp1,temp2,parp,bx,by,bz,bh;
static char model[20], c_str[81], c_new[5];
static double *p = snorm;
char answer;
FILE *wmmdat;
wmmdat = fopen("WMM.COF","r");
/* INITIALIZE CONSTANTS */
maxord = *maxdeg;
sp[0] = 0.0;
cp[0] = *p = pp[0] = 1.0;
dp[0][0] = 0.0;
a = 6378.137;
b = 6356.7523142;
re = 6371.2;
a2 = a*a;
b2 = b*b;
c2 = a2-b2;
a4 = a2*a2;
b4 = b2*b2;
c4 = a4 - b4;
/* READ WORLD MAGNETIC MODEL SPHERICAL HARMONIC COEFFICIENTS */
c[0][0] = 0.0;
cd[0][0] = 0.0;
fgets(c_str, 80, wmmdat);
S3:
if (fgets(c_str, 80, wmmdat) == NULL) goto S4;
/* CHECK FOR LAST LINE IN FILE */
for (i=0; i<4 && (c_str[i] != '\0'); i++)
{
c_new[i] = c_str[i];
c_new[i+1] = '\0';
}
icomp = strcmp("9999", c_new);
if (icomp == 0) goto S4;
/* END OF FILE NOT ENCOUNTERED, GET VALUES */
sscanf(c_str,"%d%d%lf%lf%lf%lf",&n,&m,&gnm,&hnm,&dgnm,&dhnm);
if (n > maxord) goto S4;
if (m > n || m < 0.0)
{
fprintf(stderr, "Corrupt record in model file WMM.COF\n");
exit(1);
}
if (m <= n)
{
c[m][n] = gnm;
cd[m][n] = dgnm;
if (m != 0)
{
c[n][m-1] = hnm;
cd[n][m-1] = dhnm;
}
}
goto S3;
/* CONVERT SCHMIDT NORMALIZED GAUSS COEFFICIENTS TO UNNORMALIZED */
S4:
*snorm = 1.0;
fm[0] = 0.0;
for (n=1; n<=maxord; n++)
{
*(snorm+n) = *(snorm+n-1)*(double)(2*n-1)/(double)n;
j = 2;
for (m=0,D1=1,D2=(n-m+D1)/D1; D2>0; D2--,m+=D1)
{
k[m][n] = (double)(((n-1)*(n-1))-(m*m))/(double)((2*n-1)*(2*n-3));
if (m > 0)
{
flnmj = (double)((n-m+1)*j)/(double)(n+m);
*(snorm+n+m*13) = *(snorm+n+(m-1)*13)*sqrt(flnmj);
j = 1;
c[n][m-1] = *(snorm+n+m*13)*c[n][m-1];
cd[n][m-1] = *(snorm+n+m*13)*cd[n][m-1];
}
c[m][n] = *(snorm+n+m*13)*c[m][n];
cd[m][n] = *(snorm+n+m*13)*cd[m][n];
}
fn[n] = (double)(n+1);
fm[n] = (double)n;
}
k[1][1] = 0.0;
otime = oalt = olat = olon = -1000.0;
fclose(wmmdat);
return;
我想出的将程序中的数据包含在内的代码如下:
struct wmm
{
int alpha;
int beta;
float gamma;
float delta;
float epsilon;
float zeta;
}book[90]= {{1, 0, -29496.6, 0.0, 11.6, 0.0},
{1, 1, -1586.3, 4944.4, 16.5, -25.9},
{2, 0, -2396.6, 0.0, -12.1, 0.0},
{2, 1, 3026.1, -2707.7, -4.4, -22.5},
{2, 2, 1668.6, -576.1, 1.9, -11.8},
{3, 0, 1340.1, 0.0, 0.4, 0.0},
/* 50+ similar lines of code */
{12, 8, -0.4, 0.1, 0.0, 0.0},
{12, 9, -0.4, 0.3, 0.0, 0.0},
{12, 10, 0.2, -0.9, 0.0, 0.0},
{12, 11, -0.8, -0.2, -0.1, 0.0},
{12, 12, 0.0, 0.9, 0.1, 0.0}};
for (i = 0; i < 90 && offset < buf_size; i++)
{
offset += snprintf(c_str + offset,buf_size - offset, "%d %d %7.1lf %7.1lf %7.1lf %7.1lf \n", book[i].alpha, book[i].beta , book[i].gamma , book[i].delta, book[i].epsilon, book[i].zeta);
}
sscanf(c_str,"%d%d%lf%lf%lf%lf",&n,&m,&gnm,&hnm,&dgnm,&dhnm);
问题是snprintf导致程序在每次放入程序时冻结并终止。当我编写的代码在它自己运行时,它似乎正确地创建c_str,除非我尝试查看变量n,m,gnm,hnm,dgnm和dhnm时,只显示每个变量的单个值。
答案 0 :(得分:1)
由于评论中缺少空格/格式,我需要继续回答。
首先,你有90个条目,但你可以让编译器弄清楚book
数组需要多少条目:
struct wmm {
int alpha;
int beta;
float gamma;
float delta;
float epsilon;
float zeta;
} book[] = {
{1, 0, -29496.6, 0.0, 11.6, 0.0},
{1, 1, -1586.3, 4944.4, 16.5, -25.9},
/* ... */
{12, 12, 0.0, 0.9, 0.1, 0.0}
};
而且,更重要的是,你不需要将它们放在一个字符串中,并在你手头有它们时将它们拉回来:
for(i = 0; i < sizeof(book)/sizeof(book[0]); ++i) {
n = book[i].alpha;
m = book[i].beta;
gnm = book[i].gamma;
hnm = book[i].delta;
dgnm = book[i].epsilon;
dhnm = book[i].zeta;
/* Do whatever you need to do with the above variables. */
}
对于您snprintf
所造成的缓冲区溢出,这将是一个整齐的步骤。
您的c_str
仅为char[81]
,您每次都会循环90次,并将偏移量增加到c_str
;所以,你不久就会跑到c_str
的末尾,然后你会告诉snprintf
乱写未分配的内存。因此你的段错误。