我有一个元组列表:
seqList=[('SQ010', ('sh001', '1-10')), ('SQ010', ('sh002', '5-15')), ('SQ010', ('sh003', '6-16')), ('SQ010', ('sh004', '7-17')), ('SQ020', ('sh001', '8-18')), ('SQ020', ('sh002', '9-19')), ('SQ020', ('sh003', '10-20'))]
我想将每个元素与相同的第一个数组合并以产生以下输出:
[('SQ010', ('sh001', '1-10'), ('sh002', '5-15'), ('sh003', '6-16'), ('sh004', '7-17')), ('SQ020', ('sh001', '8-18'), ('sh002', '9-19'),('sh003', '10-20'))]
我尝试使用以下代码对groupby进行尝试:
from itertools import groupby
output_list = [tuple(i[1] for i in e) for _, e in groupby(seqList, lambda x: x[0])]
print output_list
结果:
[(('sh001', '1-10'), ('sh002', '5-15'), ('sh003', '6-16'), ('sh004', '7-17')), (('sh001', '8-18'), ('sh002', '9-19'), ('sh003', '10-20'))]
我不明白为什么我松开了SQXXX部分以及如何获得所需的输出。谢谢
答案 0 :(得分:2)
SQXXX
部分是您已删除的_
变量。试试:
output_list = [(i,) + tuple(i[1] for i in e) for i, e in groupby(seqList, lambda x: x[0])]
给予:
[('SQ010', ('sh001', '1-10'), ('sh002', '5-15'), ('sh003', '6-16'), ('sh004', '7-17')), ('SQ020', ('sh001', '8-18'), ('sh002', '9-19'), ('sh003', '10-20'))]