Question

我尝试使用symfony 3.4中的guzzlehttp / guzzle捆绑包从后端向我的NodeJS测试服务器发出HTTP请求。我试图用邮递员和cURL测试我的nodeJS服务器，它可以工作，但不能在我的后端工作。

这是我的代码：

在PartnerController.php中：

    /**
     * @POST("/partner/searchNurseToUser")
     */
    public function searchNurseAction(Request $request)
    {

        $client = new Client(['base_uri' => 'http://172.18.0.5:9000']);  

        $nurseFirstname = htmlspecialchars($request->request->get('nurseFirstname'));
        $nurseLastname = htmlspecialchars($request->request->get('nurseLastname'));
        $nursePhone = htmlspecialchars($request->request->get('nursePhoneNumber'));
        $nursePostalCode = htmlspecialchars($request->request->get('nursePostalCode'));
        $nurseCity = htmlspecialchars($request->request->get('nurseCity'));


        try {
            $response = $client->request('POST', 'partner/pros/', [
                'json' => [
                    'name' => $nurseFirstname . ' ' . $nurseLastname, 
                    'city' => $nurseCity,  
                    'phone' => $nursePhone,
                    'zipcode' => $nursePostalCode

                ]
            ]);

在app.js中：

const bodyParser = require('body-parser');


const app = express();

// parse application/x-www-form-urlencoded
app.use(bodyParser.urlencoded({ extended: false })) 

// Define routes
app.use('/partner/', require('./routes/api/partner'));


const port = 9000;
app.listen(port, function() {
    console.log('Listening on port 9000!')
})

partner.js：

const router = express.Router();

router.post('/pros', async (req, res) => {
    const { name, email, phone, city, zipcode } = req.body;

    try {
        let response = {};
        if (name || email || phone || city || zipcode) {
            response = {
                "data": [
                    {
                    "civility": "F",
                    "firstname": "Adeline",
                    "lastname": "Dupont"
                    }
                ]
            }
        } else {
            response = [];
        }

        return res.json(response).status(200);
    } catch (err) {
        console.error(err.message);
        res.status(500).send('Server error');
    }
})

module.exports = router;

但是邮差返回此错误消息：

Error GuzzleHttp Message Error "Resources are not supported in serialized data. Path: GuzzleHttp\\Psr7\\Stream".

谢谢您的帮助！

Answer 1

我找到了解决方案！

只需在我的函数searchNurseAction的返回中使用JsonResponse！

   /**
     * @POST("/partner/searchNurseToUser")
     */
    public function searchNurseAction(Request $request)
    {

        $client = new Client(['base_uri' => 'http://172.18.0.5:9000']);  

        $nurseFirstname = htmlspecialchars($request->request->get('nurseFirstname'));
        $nurseLastname = htmlspecialchars($request->request->get('nurseLastname'));
        $nursePhone = htmlspecialchars($request->request->get('nursePhoneNumber'));
        $nursePostalCode = htmlspecialchars($request->request->get('nursePostalCode'));
        $nurseCity = htmlspecialchars($request->request->get('nurseCity'));

        $response = $client->request('POST', 'partner/pros/', [
            'form_params' => [
                'name' => $nurseFirstname . ' ' . $nurseLastname, 
                'city' => $nurseCity,  
                'phone' => $nursePhone,
                'zipcode' => $nursePostalCode,
                'job' => 1
                ]
                ]);


        try {
            if($response->getStatusCode() === 200 || $response->getStatusCode() === 204){
                $nurses = $response->getBody();

                $ret = array(
                    'nurses' => $nurses,
                    'status' => 200,
                );

                return new JsonResponse($nurses, 200, [], true);
            }
        } catch (\Exception $e) {
            $ret = array(
                'error' => $e->getMessage(),
            );


            return new JsonResponse($e, 500, [], true);
        }
    }

而不是：

    /**
     * @POST("/partner/searchNurseToUser")
     */
    public function searchNurseAction(Request $request)
    {

        $client = new Client(['base_uri' => 'http://172.18.0.5:9000']);

        $nurseFirstname = htmlspecialchars($request->request->get('nurseFirstname'));
        $nurseLastname = htmlspecialchars($request->request->get('nurseLastname'));
        $nursePhone = htmlspecialchars($request->request->get('nursePhoneNumber'));
        $nursePostalCode = htmlspecialchars($request->request->get('nursePostalCode'));
        $nurseCity = htmlspecialchars($request->request->get('nurseCity'));

        $response = $client->request('POST', 'partner/pros/', [
            'form_params' => [
                'name' => $nurseFirstname . ' ' . $nurseLastname, 
                'city' => $nurseCity,  
                'phone' => $nursePhone,
                'zipcode' => $nursePostalCode,
                'job' => 1
                ]
                ]);

        try {
            if($response->getStatusCode() === 200 || $response->getStatusCode() === 204){
                $nurses = $response->getBody();

                $ret = array(
                    'nurses' => $nurses,
                    'status' => 200,
                );

                $view = $this->view($ret);

            }
        } catch (\Exception $e) {
            $ret = array(
                'error' => $e->getMessage(),
            );

            $view = $this->view($ret, 500);

        }

        return $this->handleView($view);
    }

对不起，我的问题还不完整。谢谢你

GuzzleHttp请求不起作用

1 个答案: