此代码适用于单个图像,但我需要执行多个操作,因此请帮助我更改此代码
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="col">
<div><img id="img1" src="" alt="your image" style="max-width:180px;" /><output id=”result” ></div>
<div><input id="img11" onchange="readURL(this);" type="file" name="Image1" id="" style="padding:10px; background:#2d2d2d;" ></div>
</div>
<div class="col">
<div><img id="img2" src="" alt="your image" style="max-width:180px;" /><output id=”result” ></div>
<div><input id="img22" onchange="readURL(this);" type="file" name="Image1" id="" style="padding:10px; background:#2d2d2d;" ></div>
</div>
</div
答案 0 :(得分:0)
如果要选择多个图像文件并将其显示在dom上!那么您可以执行以下操作: 我想这就是您要寻找的
HTML:
<input type="file" multiple id="gallery-photo-add">
<div class="gallery"></div>
JS:
<script>
$(function() {
// Multiple images preview in browser
var imagesPreview = function(input, placeToInsertImagePreview) {
if (input.files) {
var filesAmount = input.files.length;
for (i = 0; i < filesAmount; i++) {
var reader = new FileReader();
reader.onload = function(event) {
$($.parseHTML('<img>')).attr('src', event.target.result).appendTo(placeToInsertImagePreview);
}
reader.readAsDataURL(input.files[i]);
}
}
};
$('#gallery-photo-add').on('change', function() {
imagesPreview(this, 'div.gallery');
});
});
</script>