Question

此问题是此问题的附加内容：filter multi-indexed grouped pandas dataframe

我想获得timestamp，其中value在date之后开始大于零，作为每个单独的new_date的新列id

示例输入数据：

id timestamp  date       value
1  2001-01-01 2001-05-01 1
1  2001-10-01 2001-05-01 0
1  2001-10-02 2001-05-01 1
1  2001-10-03 2001-05-01 0
1  2001-10-04 2001-05-01 1
2  2001-01-01 2001-05-01 1
2  2001-10-01 2001-05-01 0
2  2001-10-02 2001-05-01 0
2  2001-10-03 2001-05-01 0
2  2001-10-04 2001-05-01 1

想要的输出数据示例：

id timestamp  date       value new_date
1  2001-01-01 2001-05-01 1     2001-10-02
1  2001-10-01 2001-05-01 0     2001-10-02
1  2001-10-02 2001-05-01 1     2001-10-02
1  2001-10-03 2001-05-01 0     2001-10-02
1  2001-10-04 2001-05-01 1     2001-10-02
2  2001-01-01 2001-05-01 1     2001-10-04
2  2001-10-01 2001-05-01 0     2001-10-04
2  2001-10-02 2001-05-01 0     2001-10-04
2  2001-10-03 2001-05-01 0     2001-10-04
2  2001-10-04 2001-05-01 1     2001-10-04

Answer 1

如果某个组没有匹配项，则更简单的解决方案也可以工作，首先过滤Accept: application/json链掩码，将DataFrame乘以Series.gt，然后按位date替换{{1} }，然后通过DataFrame.drop_duplicates删除重复项，创建AND并最后使用Series.map：

过滤并扩展时间序列熊猫数据框

1 个答案: