我想将LIST_OF_ALL_COLLEAGUES转换为列表,但是我不知道该怎么做。
我有一个用户类,其中包含此“列出同事”字段。 我的用户类转换代码如下:
import 'package:cloud_firestore/cloud_firestore.dart';
import 'package:snagsnapper/Contants/constants.dart';
import 'package:snagsnapper/Data/colleague.dart';
class User {
User ({
this.name,
this.dateFormat,
this.listOfALLColleagues,
});
String name;
String dateFormat='dd-MM-yyyy';
List<Colleague> listOfALLColleagues;
User.fromMap(DocumentSnapshot data)
: this(
name: data[NAME],
dateFormat: data[DATE_FORMAT],
listOfALLColleagues: List<Colleague>.from(data[LIST_OF_COLLEAGUES]),
);
Map<String, dynamic> toJSON() => {
NAME : name,
DATE_FORMAT : dateFormat,
LIST_OF_COLLEAGUES : listOfALLColleagues,
};
}
我的同事班级如下:
import 'package:cloud_firestore/cloud_firestore.dart';
import 'package:snagsnapper/Contants/constants.dart';
class Colleague {
String name;
String email;
String phone;
String uniqueID;
Colleague({
this.name,
this.email,
this.phone,
this.uniqueID,
});
Colleague.fromMap(DocumentSnapshot data)
: this(
name: data[NAME],
email: data[EMAIL],
phone: data[PHONE],
uniqueID: data[UID],
);
Map<String, dynamic> toJSON() => {
NAME : name,
EMAIL : email,
PHONE : phone,
UID : uniqueID,
};
}
到目前为止,我已经尝试了几种网上见过的方法,但是都没有运气: 我尝试过:
listOfALLColleagues: List<Colleague>.from(data[LIST_OF_COLLEAGUES]),
listOfALLColleagues: List.from(data[LIST_OF_COLLEAGUES]),
listOfALLColleagues: List.castFrom(data[LIST_OF_COLLEAGUES]),
listOfALLColleagues: data[LIST_OF_COLLEAGUES] as List<Colleague>,
listOfALLColleagues: data[LIST_OF_COLLEAGUES]
.map((value) {
return Colleague.fromMap(value);
}).toList(),
我知道其中一些是相同的,但是我只想在这里提及它们。
答案 0 :(得分:1)
我设法用Json-Serial库做到了。我之前并不知道这个库,所以我发现它很容易。