如何返回列表中所有匹配项？

Question

我有以下代码。我有一个包含一堆数据的文件，我想返回所有出现在提示符下的数据。但是我刚刚返回的代码才第一次出现。我想知道如何返回所有事件。这只会返回它在列表中找到的第一个。我将如何更改以返回所有出现的事件。例如，如果我希望它返回所有符合该等级的PG13电影，而不是第一个，我将如何处理？

def getRating(titlesList,ratingList,ratingname):
    #This function will take the ratings,films and userrating parameters
    #It will look through the ratings list to search for the specific rating 
    #the user chooses
    #It then returns a list of all the films of a certain rating
    i = 0
    found = 0
    while i < len(ratingList) and found == 0:
        if ratingname == ratingList[i]:
            found = 1
        else:
            i = i + 1
    if found == 1:
        return i
    else:
        return ""

Answer 1

def getRating(titlesList,ratingList,ratingname):
    #This function will take the ratings,films and userrating parameters
    #It will look through the ratings list to search for the specific rating 
    #the user chooses
    #It then returns a list of all the films of a certain rating
    i = 0
    found = 0
    listOfFilms = []
    while i < len(ratingList):
        if ratingname == ratingList[i]:
            found = 1
            listOfFilms.append(ratingList[i])
        else:
            i += 1
    if found == 1:
        return listOfFilms
    else:
        return "There's no occurrences"

您的错误是您返回标志i，这对于引用任何内容都可能是无用的。而是创建一个空列表并附加每个匹配项。

希望这会有所帮助：）