Question

我有一个列表，其中列出了分配给用户的所有任务，如下所示

public function index($data){
    print_r($data);
}

点击每个任务都应打开一个详细信息页面。

  @override
  void initState() {
    crudObj.getassignedData().then((results) {
      setState(() {
        Task = results;
      });
    });
    super.initState();
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      drawer: newdrawer(),
      appBar: newappbar(),
      body: _TaskList(),
      floatingActionButton: FloatingActionButton(
        foregroundColor: Colors.black54,
        backgroundColor: Colors.blue,
        elevation: 0,
        child: Icon(Icons.add),
        onPressed: () {
          addDialog(context);
        },
      ),
      floatingActionButtonLocation: FloatingActionButtonLocation.centerFloat,
    );
  }

  // ignore: non_constant_identifier_names
  Widget _TaskList() {
    if (Task != null) {
      return ListView.builder(
        itemCount: Task.documents.length,
        padding: EdgeInsets.all(5.0),
        itemBuilder: (context, i) {
          return new ListTile(
            title: Text(Task.documents[i].data['Title']),
            subtitle: Text(Task.documents[i].data['Summary']),
            onTap: (){
              Navigator.push(context,
              MaterialPageRoute(builder: (context)=>
              taskdetail(Task.documents[i])
              )
              );
            },
          );
        },
      );
    } else {
      return Text('Loading, Please wait..');
    }
  }

}

我收到此错误：

class _taskdetailState extends State<taskdetail> {
  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: Text('Details'),
      ),
      body: ListView.builder(itemBuilder: (context,i)
      {
        return ListTile(
          title: Text(widget.documents[i]['Title']),
        );
      }
      ),
    );
  }
}

Answer 1

您可以尝试

title: Text("${Task.documents[i].data['Title']}"),
subtitle: Text("${Task.documents[i].data['Summary']}"),

抖动中'int'类型不是'key'错误的'String'类型的子类型

1 个答案: