Question

代码：

#read through
name = input("Enter file:")
if len(name) < 1 : name = "mbox-short.txt"
handle = open(name)

counts = dict()
for line in handle:
    if not line.startswith('From '): continue
    line = line.split()
    line = line[5]
    time = line.split(':')
    time = time[0]
    counts[time] = counts.get(time, 0) + 1
print(sorted(counts.items()))

当前输出：

[('04', 3), ('06', 1), ('07', 1), ('09', 2), ('10', 3), ('11', 6), ('14', 1), ('15', 2), ('16', 4), ('17', 2), ('18', 1), ('19', 1)]

所需的输出：

我正在做一个作业，我的目标是从文件中提取数据，然后对数据进行计数，排序和列出。我已经基本完成了，但是输出出现了问题。基本上，我无法使代码以所需的垂直格式输出。如何获得所需的输出格式？

此外，如果有更好的方式来做我正在做的事情，请在回答中包括该内容。

谢谢

Answer 1

尝试一下：

#read through
name = input("Enter file:")
if len(name) < 1 : name = "mbox-short.txt"
handle = open(name)

counts = dict()
for line in handle:
    if not line.startswith('From '): continue
    line = line.split()
    line = line[5]
    time = line.split(':')
    time = time[0]
    counts[time] = counts.get(time, 0) + 1
for key,value in sorted(counts.items()):
    print(key , value)

Answer 2

尝试一下：

[print(x, y) for x, y in sorted(counts.items())]

您可以使用join()

将列表转换为字符串，而不是在每次迭代中进行打印

print('\n'.join([x[0] + " " + str(x[1]) for x in sorted(counts.items())]))

如何在Python 3中使输出垂直打印而不是水平打印？

2 个答案: