Question

package com.gpcoder.lambda;

import java.util.ArrayList;
import java.util.List;
import java.util.stream.Stream;

class Product {
 int id;
 String name;
 float price;

    public Product(int id, String name, float price) {
        super();
        this.id = id;
        this.name = name;
        this.price = price;
    }
}

public class LambdaExpression6 {

    public static void main(String[] args) {

        List<Product> list = new ArrayList<>();
        list.add(new Product(1, "Samsung A5", 17000f));
        list.add(new Product(3, "Iphone 6S", 65000f));
        list.add(new Product(2, "Sony Xperia", 25000f));
        list.add(new Product(4, "Nokia Lumia", 15000f));
        list.add(new Product(5, "Redmi4 ", 26000f));
        list.add(new Product(6, "Lenevo Vibe", 19000f));

        // using lambda to filter data
        Stream<Product> filtered_data = list.stream().filter(p -> p.price > 20000);

        // using lambda to iterate through collection
        filtered_data.forEach(product -> System.out.println(product.name + ": " + product.price));
    }
}

研究Lambda表达式时，我看到带有super()关键字的代码。而且我只知道 Java中的super关键字是一个用于引用直接父类对象的引用变量。但是在此代码中，关键字super()没有参数，也没有父类。那么为什么我们在那里super()。

没有参数的super（）关键字

0 个答案: