如何在没有数据建模的情况下对猫鼬数据进行CRUD

Question

我现在在互联网上搜索了2天，没有找到答案，

const mongoose = require('mongoose');

const channelsSchema = new mongoose.Schema(
    {
        stateName: {
            type: String,
            required: [true, 'A state must have a name'],
            unique: true,
            index:true
        },
        id: {
            type:String
        },
        Name: {
            type:String
        },
        **anyThing: [Object]
    },
    { strict: false }
);

const Channels = mongoose.model('Channels', channelsSchema);

module.exports = Channels;

有什么办法可以使任何东西接受任何东西吗？

注意：这不是一个大项目，我也不担心安全性。它只在本地运行

Answer 1

您可以将{strict: false}作为第二个参数传递给Schema来实现。

const mongoose = require('mongoose');

const channelsSchema = new mongoose.Schema({}, {strict: false})
const Channels = mongoose.model('Channels', channelsSchema);
module.exports = Channels;