Question

我无法在应用程序中对“登录”按钮执行点击操作。

下面是HTML代码。您可以在最后一行找到确切的按钮元素。

<div class="form-group dl-padding-10">

                        <select class="form-control form-control-solid" name="SelectedRoleID" id="SelectedRoleID" onchange="removeBorderColor()" required="">
                                <option id="default_val" selected="" disabled="" hidden="">Profile </option>
                                    <option value="15">Service Consultant</option>
                                    <option value="11">DLBO Developer</option>
                                    <option value="16">Admin Agent</option>
                                    <option value="17">Team Leader</option>
                                    <option value="18">Manager</option>
                                    <option value="19">CV Mandator</option>
                                    <option value="20">CV Agent</option>
                                    <option value="21">Forensics Agent</option>
                        </select>
                        <div class="dl-align-left" id="show_text" style="color:red">
                            &nbsp;
                        </div>

                    </div>

                    <div class="circle1-mask form-group" id="FingerprintContent" style="height:140px;z-index:2; background-image: none;">
                        <img src="Assets/img/fingerprint4.gif" id="fingerprint-img" data-status="active" style="height:140px; width:100px;" onclick="DeviceScript.scanFingerPrint(event)">
                    </div>
                        <div class="form-group dl-padding-10">
                            <button type="submit" id="register-btn" class="btn btn-block dl-button-primary dl-no-margin">Sign In (For Testing Purpose Only)</button>
                        </div>


                </div>
            </div>
</form>    </div>
</div>

请帮助我使用合适的xpath来执行登录按钮上的点击操作。

还可以找到尝试的代码图像。Code

Xpath=”//button[contains(text(), 'Sign In (For Testing Purpose Only)')]”
(Or)

IWebElement Signin = driver.FindElement(By.Id("register-btn"));
            Signin.Click();
(Or)

IWebElement Signinbutton = driver.FindElement(By.XPath("//button[contains(text(), 'Sign In (For Testing Purpose Only)')]"));


            Actions action = new Actions(driver);
            
            action.MoveToElement(Signinbutton).Click().Perform();

The error which i get:
OpenQA.Selenium.ElementClickInterceptedException : element click intercepted: Element <button type="submit" id="register-btn" class="btn btn-block dl-button-primary dl-no-margin">...</button> is not clickable at point (758, 646). Other element would receive the click: <div class="footer navbar-fixed-bottom">...</div>

Answer 1

由于错误引用了页脚，因此您似乎缺少了一些html。

不是线程休眠的支持者，而是尝试一个，看看线程休眠是否允许页面加载。我想知道您的页面是否仍在加载并尝试单击。如果睡眠正常，我将其删除并移至element或尝试单击java。

Thread.Sleep(1000);
driver.FindElement(By.XPath("//button[contains(text(), 'Sign In')]")).Click();
driver.FindElement(By.Id("register-btn")).Click();

Answer 2

尝试使用javascript：

IWebElement Signinbutton = driver.FindElement(By.XPath("//button[contains(text(), 'Sign In (For Testing Purpose Only)')]"));
IJavaScriptExecutor javascriptExecutor = (IJavaScriptExecutor)driver;
executor.ExecuteScript("arguments[0].click();", Signinbutton );

Answer 3

您收到的异常是因为您要单击的按钮在此元素的后面 <div class="footer navbar-fixed-bottom">...</div> 这似乎是页面的页脚。

您可以尝试以下任何步骤来解决该问题

滚动到登录按钮下方的任何元素（如果有）。您可以为此使用以下代码：

protected boolean scrollToElement(WebElement element) throws NoSuchElementException, StaleElementReferenceException { try { jsExecutor.executeScript("arguments[0].scrollIntoView(true);", element); return true; } catch (NoSuchElementException e) { logError("Element Not found exception when scrolling to element (JavaScript)", e); throw e; } catch (StaleElementReferenceException e) { logError("Stale element exeption when scrolling to element (JavaScript)", e); throw e; } }
1. 如果用于接受cookie 或类似的内容，则关闭页脚，或者也可以将“自定义CSS”应用于该元素以将其隐藏，然后尝试单击该元素。
String css= "display:none !important;" protected void addCustomCSS(WebElement webElement, String css) { registerCall(new Object() { }.getClass().getEnclosingMethod().getName()); try { String style = (String) jsExecutor.executeScript("arguments[0].getAttribute('style')", webElement); jsExecutor.executeScript("arguments[0].setAttribute('style', " + css + ")", webElement); stylesQueue.add(style); } catch (Exception e) { e.printStackTrace(); } }

元素单击拦截异常

3 个答案: