Question

我有两个如下表

NA_table
+----+-------+-------+---------------+---------------------+-----+
| id | nname  | phone |      nip       |        ntime      | iid |
+----+-------+-------+---------------+---------------------+-----+
|  1 | john  | +xxxx |  192.168.1.10 | 2020-04-21 11:10:10 |  23 |
|  2 | bill  | +xxxx |  192.168.1.11 | 2020-04-21 12:10:10 |  44 |
|  3 | husky | +xxxx |  192.168.1.12 | 2020-04-21 13:10:10 |  44 |
|  4 | lab   | +xxxx |  192.168.1.13 | 2020-04-21 14:10:10 |  33 |
|  5 | bill  | +xxxx |  192.168.1.12 | 2020-04-21 11:10:15 |  44 |
|  6 | cal   | +xxxx |  192.168.1.13 | 2020-04-21 16:10:10 |  12 |
|  7 | jess  | +xxxx |  192.168.1.11 | 2020-04-21 17:10:10 |  90 |
|  8 | minn  | +xxxx |  192.168.1.12 | 2020-04-21 18:10:10 |  44 |
|  9 | jess  | +xxxx |  192.168.1.11 | 2020-04-21 17:10:10 |  21 |
+----+-------+-------+---------------+---------------------+-----+


CD_table
+----+--------------+---------------------+-------+
| cid |     cip      |       ctime        | other |
+----+--------------+---------------------+-------+
|  1 | 192.168.1.11 | 2020-04-21 03:22:19 | text  |
|  2 | 192.168.1.12 | 2020-04-21 03:10:10 | text  |
|  3 | 192.168.1.11 | 2020-04-21 06:11:12 | text  |
|  4 | 192.168.1.19 | 2020-04-21 06:10:03 | text  |
|  5 | 192.168.1.22 | 2020-04-21 13:10:10 | text  |
|  6 | 192.168.1.11 | 2020-04-21 14:14:17 | text  |
|  7 | 192.168.1.12 | 2020-04-21 16:09:10 | text  |
|  8 | 192.168.1.11 | 2020-04-22 09:07:11 | text  |
+----+--------------+---------------------+-------+

使用这两个表我要运行此查询

SELECT
CD_table.ctime AS CTIME,
CD_table.cip AS CIP,
CD_table.other AS OTHER,
NA_table.phone AS PHONE,
FROM NA_table
LEFT JOIN CD_table 
ON NA_table.nip = CD_table.cip 
WHERE
NA_table.NAIID = '44'
AND
NA_table.ntime between '2020-04-21 11:10:00' AND '2020-04-21 11:10:59'
AND
CD_table.ctime between '2020-04-21 00:10:00' AND '2020-04-21 23:59:59'

这给了我这个结果。

+----------------------+---------------+-------+-------+
|        CTIME         |      CIP      | OTHER | PHONE |
+----------------------+---------------+-------+-------+
| 2020-04-21 03:22:19  |  192.168.1.11 | text  | +xxxx |
| 2020-04-21 03:10:10  |  192.168.1.12 | text  | +xxxx |
| 2020-04-21 06:11:12  |  192.168.1.11 | text  | +xxxx |
| 2020-04-21 14:14:17  | 192.168.1.11  | text  | +xxxx |
| 2020-04-21 16:09:10  |  192.168.1.12 | text  | +xxxx |
+----------------------+---------------+-------+-------+

但是我希望我的输出按CTIME排序，并且只打印每个CD_table记录的最后匹配记录，像这样

+---------------------+---------------+-------+-------+
|        CTIME        |      CIP      | OTHER | phone |
+---------------------+---------------+-------+-------+
| 2020-04-21 14:14:17 | 192.168.1.11  | text  | +xxxx |
| 2020-04-21 16:09:10 |  192.168.1.12 | text  | +xxxx |
+---------------------+---------------+-------+-------+

我可以在其中执行DESC和LIMIT部分查询。还是我可以拆分查询的其他方法。

Answer 1

您可以使用子查询过滤cd_table以获得给定间隔内的最新记录。

此外，由于您的查询未从na_table返回任何内容，因此我将联接设置为exists条件-在这种情况下，这通常会更有效。

select c.ctime, c.cip, c.other
from cd_table c
where 
    c.ctime = (
        select max(c1.ctime) 
        from cd_table c1 
        where 
            c1.cip = c.cip
            and c1.ctime >= '2020-04-21 00:10:00'
            and c1.ctime <  '2020-04-22'
    )
    and exists (
        select 1 
        from na_table n
        where 
            n.nip = c.cip
            and n.naid = 44 
            and n.ntime >= '2020-04-21 11:10:00'
            and n.ntime <  '2020-04-21 11:11:00'
    )

请注意，我将日期条件重写为半开间隔（这样可以避免每次都拖尾59秒）。

为提高性能，请考虑以下索引：

cd_table(cip, ctime)
na_table(nip, naid, time)

在other的索引中添加cd_table可能会带来额外的好处。

Answer 2

如果您使用的是MySQL 8.0，则可以使用row_number()

SELECT
    CTIME,
    CIP,
    OTHER
from
(
    SELECT
    CD_table.ctime AS CTIME,
    CD_table.cip AS CIP,
    CD_table.other AS OTHER
    row_number() over (order by CTIME desc) as rnk
    FROM NA_table
    LEFT JOIN CD_table 
    ON NA_table.nip = CD_table.cip 
    WHERE
    NA_table.NAIID = '44'
    AND
    NA_table.ntime between '2020-04-21 11:10:00' AND '2020-04-21 11:10:59'
    AND
    CD_table.ctime between '2020-04-21 00:10:00' AND '2020-04-21 23:59:59'
) val
where rnk = 1
order by
    CTIME

左联接两个MySql表，而第二个表按desc排序并限制为1

2 个答案: