使用此代码:
trace = go.Scatter(x=[1,2,3],
y=[1,2,3],
name = "chart1",
mode="markers+text",
opacity = 1)
layout = dict(width=800,
height=600,autosize=True,margin=dict(
l=50,
r=50,
b=100,
t=100,
pad=4
))
iplot(dict(data=[trace], layout=layout))
渲染器:
如何在此图表中包含一条包含对应于x值[[3,1,4]
的y值1,2,3]
的线?
此代码:
# libraries
import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
# Data
df=pd.DataFrame({'x': range(1,11), 'y1': np.random.randn(10), 'y2': np.random.randn(10)+range(1,11), 'y3': np.random.randn(10)+range(11,21) })
plt.plot(('x', 'y1'), data=df, marker='o', markerfacecolor='blue', markersize=12, color='skyblue', linewidth=4)
plt.plot(('x', 'y2'), data=df, marker='o', markerfacecolor='blue', markersize=12, color='skyblue', linewidth=4)
plt.plot(('x', 'y3'), data=df, marker='o', markerfacecolor='blue', markersize=12, color='skyblue', linewidth=4, linestyle='dashed', label="toto")
plt.legend()
达到类似的效果,但缺少情节样式:
我还尝试在散点图的创建中包括y值:
y=[[1,2,3] , [3,1,4]]
但是图表未按预期呈现:
答案 0 :(得分:1)
添加另一条痕迹:
trace = go.Scatter(...) # your original trace
trace2 = go.Scatter(x=[1,2,3], y=[3,1,4], name='chart2')
layout = ...
iplot(dict(data=[trace, trace2], layout=layout))
答案 1 :(得分:1)
您也可以这样做:
fig = go.Figure()
fig.add_Trace(your trace)
fig.add_trace(go.Scatter(x=[1,2,3], y=[3,1,4],
mode='lines',
name='lines'))
fig.add_layout(dict(width=800,
height=600,autosize=True,margin=dict(
l=50,r=50,b=100,t=100, pad=4))
fig.show()