Question

我目前正在一个项目中，我们必须检查密码强度并生成一个强密码，但是在为退出程序提供一种方法的过程中，我遇到了障碍，无法找到解决方法。进展。我尝试过break和sys.exit()，但似乎都没有用。我想当他们输入[3]然后输入['yes']时，程序结束，但是它只是返回第一个问题。我还尝试了while = True：，但成功率更低。

count = 0
while (count < 1):

    while True:
        choice = input ("Do you want to: 1) Check a password 2) Generate a Password, or 3) Quit? . [1/2/3]? : ")
        if choice in ['1', '2', '3']:
            break
    if choice == "1":
        while True:
            checkyes = input ("you want to check a password, correct? [yes/no]")
            if checkyes in ['yes', 'no']:
               break
    elif choice == "2":
        while True:
            genyes = input ("you want to generate a password, correct? [yes/no]")
            if genyes in ['yes', 'no']:
                break
    else:
        while True:
            quityes = input ("you want to quit, correct? [yes/no]")
            if quityes in ['yes', 'no']:
                break
                if choice == "yes":
                    count = count + 1
                else:
                    pass

Answer 1

您正在为退出条件检查错误的变量。您需要检查quityes：

count = 0
while (count < 1):

    while True:
        choice = input ("Do you want to: 1) Check a password 2) Generate a Password, or 3) Quit? . [1/2/3]? : ")
        if choice in ['1', '2', '3']:
            break
    if choice == "1":
        while True:
            checkyes = input ("you want to check a password, correct? [yes/no]")
            if checkyes in ['yes', 'no']:
               break
    elif choice == "2":
        while True:
            genyes = input ("you want to generate a password, correct? [yes/no]")
            if genyes in ['yes', 'no']:
                break
    else:
        while True:
            quityes = input ("you want to quit, correct? [yes/no]")
            if quityes in ['yes', 'no']:
               if quityes == 'yes'
                    count += 1
                    break
               else:
                   pass

输出：

Do you want to: 1) Check a password 2) Generate a Password, or 3) Quit? . [1/2/3]? : 3
you want to quit, correct? [yes/no]yes

Process finished with exit code 0

Answer 2

2个问题：

break语句在递增计数之前执行

您将choice上的quityes改为'yes'

if quityes in ['yes', 'no']:       
    if quityes == "yes":
        count = count + 1
    else:
         pass
    break

Answer 3

您可以尝试导入sys并将中断替换为sys.exit（）。

想想中断没有起作用的原因是因为它脱离了第一个循环，但没有脱离更大的循环。

Python“ while”循环不会终止

3 个答案: