我使用此代码在iphone中从我的应用程序发布
NSString *title=[NSString stringWithFormat:@"Posted from Poems of Love v2 iPhone/iPod/iPad touch app - { Poem Name: "];
//& titletext.text & ""\",";
NSString *alltitle= [title stringByAppendingString:poemtitle.text];
alltitle= [alltitle stringByAppendingString:@" } - { Author:"];
alltitle= [alltitle stringByAppendingString:authorname.text];
NSString *alltitle1= [alltitle stringByAppendingString:@" }"];
NSString *list = poembody.text;
NSString *kAppId=@"numid";
NSMutableDictionary* params = [NSMutableDictionary dictionaryWithObjectsAndKeys:
kAppId, @"app_id",
@"http://www.poemsofloveapp.com", @"link",
@"http://3.bp.blogspot.com/_co4MVQE_2l0/TPRh6TBjaZI/AAAAAAAAAOg/E0kgWLd4ieE/s1600/poemsoflovev2logo.png", @"picture",
alltitle1, @"name",
@"\nhttp://www.poemsofloveapp.com - Join us on facebook!\n", @"caption",
list, @"description",
@"",@"message",
nil];
[mainDelegate._session dialog:@"feed" andParams:params andDelegate:self];
对话框显示我点击跳过或发布,然后第二个对话框显示为空!没有消息就没什么了
为什么会这样?
答案 0 :(得分:0)
我的错误对不起我们打电话给[mainDelegate._session对话框:@“feed”andParams:params andDelegate:self]; 以前我知道两次愚蠢!!!