Question

我在两个数据帧中读取了两个不同的csv。我想将df1 ['building_type]列与df2 ['model']匹配，并将相应的行附加到df1。

数据框1：

data = [{'length': '34', 'width': '58.5', 'height': '60.2', 'building_type': ['concrete','wood','steel','laminate']},
       {'length': '42', 'width': '33', 'height': '23', 'building_type': ['concrete_double','wood_double','steel_double']}]
df1 = pd.DataFrame(data)

print(df1)

数据框2：


data2 = [{'type': 'A1', 'floor': '2', 'model': ['wood','laminate','concrete','steel']},
       {'type': 'B3', 'floor': '4',  'model': ['wood_double','concrete_double','steel_double']}]
df2=pd.DataFrame(data2)
print(df2)

最终数据框：

   length   width   height  building_type                                 type  floor
0   34      58.5    60.2   [concrete, wood, steel, laminate]              A1    2
1   42      33      23     [concrete_double, wood_double, steel_double]   B3    4

Answer 1

<link rel="stylesheet" href="../src/assets/css/styles.css" type="text/css">在这里似乎是必需的工具，但是我们需要一个不变的dtype。 pd.merge是可变的，不能加入。我们可以将list（可变）转换为list或tuple，它们都是不可变的，可以用来加入。由于示例输出显示顺序无关紧要，因此我选择了frozenset。

代码如下：

frozenset

我的机器上的输出：

import pandas as pd

data = [{'length': '34', 'width': '58.5', 'height': '60.2', 'building_type': ['concrete','wood','steel','laminate']},
       {'length': '42', 'width': '33', 'height': '23', 'building_type': ['concrete_double','wood_double','steel_double']}]
df1 = pd.DataFrame(data)
print(df1)

data2 = [{'type': 'A1', 'floor': '2', 'model': ['wood','laminate','concrete','steel']},
       {'type': 'B3', 'floor': '4',  'model': ['wood_double','concrete_double','steel_double']}]
df2=pd.DataFrame(data2)
print(df2)


# Note: Merge fails on mutable dtype
# pd.merge(df1, df2, left_on='building_type', right_on='model')
# Produces `TypeError: unhashable type: 'list'`

# Convert mutable type to immutable type and merge.
# `tuple` is best if order matters for you. I am assuming that the
# order doesn't matter based on the sample output, so `frozenset` is more
# appropriate.
df1['building_type'] = df1['building_type'].apply(frozenset)
df2['model'] = df2['model'].apply(frozenset)

# Now, merge. Note that since column names are different both
# 'building_type' and 'model' would be retained. You can remove one of them.
final_df = pd.merge(df1, df2, left_on='building_type', right_on='model')
final_df = final_df.drop(['model'], axis=1)
print(final_df)

将数据框的列与列表值匹配，并将数据框的行与追加

1 个答案: