如何更改此查询,以便在添加2011-01-02行后仍然显示2011-01-01收到的0 flotsam?
mysql> SELECT * FROM Items;
+---------+
| Name |
+---------+
| widgets |
| things |
| stuff |
| flotsam |
| jetsam |
+---------+
mysql> SELECT * FROM Received;
+---------+---------------+-------------+----------+
| Name | invoiceNumber | invoiceDate | Quantity |
+---------+---------------+-------------+----------+
| widgets | 1 | 2011-01-01 | 1 |
| widgets | 2 | 2011-01-01 | 2 |
| things | 3 | 2011-01-01 | 3 |
| things | 4 | 2011-01-01 | 4 |
| stuff | 5 | 2011-01-01 | 5 |
| jetsam | 7 | 2011-01-01 | 7 |
+---------+---------------+-------------+----------+
mysql> SELECT Name, IFNULL(SUM(Quantity),0)
-> FROM Items AS I
-> LEFT JOIN Received AS R
-> USING (Name)
-> WHERE invoiceDate='2011-01-01' OR invoiceDate IS NULL
-> GROUP BY Name;
+---------+-------------------------+
| Name | IFNULL(SUM(Quantity),0) |
+---------+-------------------------+
| flotsam | 0 |
| jetsam | 7 |
| stuff | 5 |
| things | 7 |
| widgets | 3 |
+---------+-------------------------+
mysql> INSERT INTO Received VALUES ('flotsam',8,'2011-01-02',8);
mysql> SELECT Name, IFNULL(SUM(Quantity),0)
-> FROM Items AS I
-> LEFT JOIN Received AS R
-> USING (Name)
-> WHERE invoiceDate='2011-01-01' OR invoiceDate IS NULL
-> GROUP BY Name;
+---------+-------------------------+
| Name | IFNULL(SUM(Quantity),0) |
+---------+-------------------------+
| jetsam | 7 |
| stuff | 5 |
| things | 7 |
| widgets | 3 |
+---------+-------------------------+
答案 0 :(得分:1)
使用:
SELECT i.name,
COALESCE(SUM(r.quantity), 0) AS total_quantity
FROM ITEMS i
LEFT JOIN RECEIVED r ON r.name = i.name
AND r.invoicedate = '2011-01-01'
GROUP BY i.name
在JOIN之前应用OUTER JOIN(LEFT,RIGHT)的ON
子句中提供的条件。 WHERE子句中的条件(对于OUTER JOINed的表)在 JOIN后应用 。