Question

我有一个名为Entity的表，该表仅包含一个ID int作为主键。我也有许多任务表（Task1, Task2, Task3, ...）。这些任务表有许多单独的列，但共有三列：

列time_created datetime2(7)的默认设置为getdate()
他们自己的ID int PK
外键ID_Entity（当然是实体表的PK）。

CREATE TABLE [dbo].[Task1]
(
    [ID_Task1] [int] IDENTITY(1,1) NOT NULL,
    [describer] [nvarchar](30) NOT NULL,
    [ID_Entity] [int] NOT NULL,
    [timestamp] [datetime2](7) NOT NULL,
    [individual_task_value] [float] NOT NULL,

    CONSTRAINT [PK_Task1] 
        PRIMARY KEY CLUSTERED ([ID_Task1] ASC)
                    WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, 
                          IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, 
                          ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

ALTER TABLE [dbo].[Task1] 
    ADD CONSTRAINT [DF_Task1_timestamp] DEFAULT (GETDATE()) FOR [timestamp]
GO

ALTER TABLE [dbo].[Task1] WITH CHECK 
    ADD CONSTRAINT [FK_Task1_Entity] 
        FOREIGN KEY([ID_Entity]) REFERENCES [dbo].[Entity] ([id])
GO

ALTER TABLE [dbo].[Task1] CHECK CONSTRAINT [FK_Task1_Entity]
GO

因此，基本上一个实体可以具有多个不同类型的任务。

创建一个连接所有这些表的查询是否可行，从而为我提供一个实体的不同任务（按日期时间排序）？

说我查询ID为1的实体，并获得分配给它的所有任务的列表：

+-----------+------------------+-------+---------+
| ID_ENTITY |     DATETIME     | TASK  | TASK_ID |
+-----------+------------------+-------+---------+
|         1 | 2020.03.01 17:30 | task1 |       1 |
|         1 | 2020.03.01 17:40 | task2 |       1 |
|         1 | 2020.03.02 06:30 | task1 |       2 |
|         1 | 2020.03.02 06:31 | task3 |       1 |
|         1 | 2020.03.02 06:32 | task2 |       2 |
|         1 | 2020.03.02 08:32 | task2 |       3 |
+-----------+------------------+-------+---------+

（这里的ID_ENTITY列毫无意义，仅作演示之用）

Answer 1

您对问题的描述对我来说像UNION。

SELECT ID_Entity,  [timestamp], 'Task1' AS Task, [ID_Task1] AS TaskID
FROM Task1
WHERE ID_Entity = 1

UNION ALL

SELECT ID_Entity,  [timestamp], 'Task2' AS Task, [ID_Task2] AS TaskID
FROM Task2
WHERE ID_Entity = 1

UNION ALL

SELECT ID_Entity,  [timestamp], 'Task3' AS Task, [ID_Task3] AS TaskID
FROM Task3
WHERE ID_Entity = 1

UNION ALL

...

ORDER BY [timestamp];

Answer 2

一个简单的UNION ALL就可以了：

select *
from (
  select [ID_Entity], [timestamp], describer, [ID_Task1] as task_id
    from [dbo].[Task1] where [ID_Entity] = 123
  union all 
  select [ID_Entity], [timestamp], describer, [ID_Task2]
    from [dbo].[Task2] where [ID_Entity] = 123
  union all 
  select [ID_Entity], [timestamp], describer, [ID_Task3]
    from [dbo].[Task3] where [ID_Entity] = 123
) x
order by timestamp

Answer 3

您应该为此编写一个递归查询

查询联接多个表

3 个答案: