阿波罗嵌套查询

Question

如何从对象的嵌套数组中获取值？

这是我的API外观：

{
  "id": 7,
  "code": "ABC123",
  "name": "Abu Bakar Enterprise",
  "speCompanyDetails": [
    {
      "id": 1,
      "speCompanyId": 7,
      "registrationType": "2",
      "registrationNo": "12345678",
      "registrationYear": 2005,
      "annualIncome": 100000,
    }
  ]
}

我的目标是我想获取代码和名称的价值，但同时我也想从speCompanyDetails.annualIncome获取价值

当前我的查询类似于这样：

const SUPPLIER_INFO_QUERY = gql`
query SupplierInfoQuery($mainSuppId: String!) {
    supplierInfo(id: $mainSuppId)
        @rest(path: "services/supplier/api/spe-companies/{args.id}", method: "GET", type: "SupplierInfo") {
            id
            name
            code
            speCompanyDetails
    }
  }
`;

但是anuualIncome的值未定义。

Answer 1

const SUPPLIER_INFO_QUERY = gql query SupplierInfoQuery($mainSuppId: String!) { supplierInfo(id: $mainSuppId) @rest(path: "services/supplier/api/spe-companies/{args.id}", method: "GET", type: "SupplierInfo") { id name code speCompanyDetails{ annualIncome } } } ;