我如何制作这样的交叉表查询?
TopItem1 TopItem2 Category1 Ca1Item1 Ca1Item2 Category2 Ca2Sub1 Ca2Sub1It1 Ca2Sub1It2 Ca2Sub2 Ca2Sub2It1
Group1 1 3 6 2 4 4 3 1 2 1 1
Group2 3 1 0 0 0 5 4 2 2 1 1
即。交叉表查询,每个类别的总计。
带有列标题的树结构表如下所示:
tSource
Key Value Parent
1 TopItem1
2 TopItem2
3 Category1
4 Category2
5 Ca1Item1 3
6 Ca1Item2 3
7 Ca2Sub1 4
8 Ca2Sub2 4
9 Ca2Sub1It1 7
10 Ca2Sub1It2 7
11 Ca2Sub2It1 8
具有行标题和要计算的值的表是您期望的那些。
现在我知道创建一个适用于任何深度树的查询是完全不可能的,但是如果我只有3个级别如图所示,那么如何获得交叉表查询以显示类别总数?
答案 0 :(得分:0)
对于相对浅的“树深度”,您可以使用UNION的自我JOIN来匹配子记录中的金额与其父母和祖父母的金额。例如,使用名为[tbl]的表
Key Value Parent Amount GroupName
--- ---------- ------ ------ ---------
1 TopItem1 5 Group1
2 TopItem2 6 Group1
3 Category1 7 Group1
4 Category2 8 Group1
5 Ca1Item1 3 20 Group1
6 Ca1Item2 3 40 Group1
7 Ca2Sub1 4 60 Group1
8 Ca2Sub2 4 80 Group1
9 Ca2Sub1It1 7 400 Group1
10 Ca2Sub1It2 7 500 Group1
11 Ca2Sub2It1 8 600 Group1
查询
SELECT t.Value, t.Amount, t.GroupName FROM tbl t
UNION ALL
SELECT t2.Value, t1.Amount, t1.GroupName
FROM
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
UNION ALL
SELECT t3.Value, t1.Amount, t1.GroupName
FROM
(
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
)
INNER JOIN
tbl t3
ON t2.Parent = t3.Key
将返回
Value Amount GroupName
---------- ------ ---------
TopItem1 5 Group1
TopItem2 6 Group1
Category1 7 Group1
Category2 8 Group1
Ca1Item1 20 Group1
Ca1Item2 40 Group1
Ca2Sub1 60 Group1
Ca2Sub2 80 Group1
Ca2Sub1It1 400 Group1
Ca2Sub1It2 500 Group1
Ca2Sub2It1 600 Group1
Category1 20 Group1
Category1 40 Group1
Category2 60 Group1
Category2 80 Group1
Ca2Sub1 400 Group1
Ca2Sub1 500 Group1
Ca2Sub2 600 Group1
Category2 400 Group1
Category2 500 Group1
Category2 600 Group1
所以如果我们将它包装在交叉表查询中
TRANSFORM Sum([Amount]) AS whatever
SELECT [GroupName]
FROM
(
SELECT t.Value, t.Amount, t.GroupName FROM tbl t
UNION ALL
SELECT t2.Value, t1.Amount, t1.GroupName
FROM
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
UNION ALL
SELECT t3.Value, t1.Amount, t1.GroupName
FROM
(
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
)
INNER JOIN
tbl t3
ON t2.Parent = t3.Key
)
GROUP BY [GroupName]
PIVOT [Value]
我们得到了
GroupName Ca1Item1 Ca1Item2 Ca2Sub1 Ca2Sub1It1 Ca2Sub1It2 Ca2Sub2 Ca2Sub2It1 Category1 Category2 TopItem1 TopItem2
--------- -------- -------- ------- ---------- ---------- ------- ---------- --------- --------- -------- --------
Group1 20 40 960 400 500 680 600 67 1648 5 6