我有一个作为表单的React按钮,我打算在单击Button时提交表单。不幸的是,当我单击按钮时,什么也没有发生,并且页面仅重新加载。即使当我只是尝试输出到控制台时,也没有任何反应,但是当您检查网络时,您可能会看到正在执行操作。
下面是我的代码,它只是一个简单的登录表单和验证用户输入的功能。单击按钮时,我需要按钮来调用函数 handleSubmit 。
export default function Signin() {
const classes = useStyles();
const [username, setUsername] = useState('');
const [password, setPassword] = useState('');
const [usernameError, setUsernameError] = useState('');
const [passwordError, setPasswordError] = useState('');
const validateUsername = () => {
setUsernameError(username.length > 3 ? null : 'Username must be longer than 3 characters')
}
const validatePassword = () => {
setPasswordError(password.length > 7 ? null : 'Password must be longer than 8 characters')
}
const handleSubmit = () => {
//const { history } = this.props;
console.log('testing button')
}
return (
<Grid
className={classes.root}
component="main"
container
>
<CssBaseline />
<Grid
className={classes.image}
item
md={4}
sm={7}
xs={false}
/>
<Grid
component={Paper}
elevation={6}
item
md={8}
sm={5}
square
xs={12}
>
<MuiThemeProvider theme={theme}>
<div className={classes.paper}>
<img
alt="logo"
src={process.env.PUBLIC_URL + '/images/....'}
/>
<Typography
component="h1"
style={{ color: '#E60000' }}
variant="h5"
>
Sign In
</Typography>
<form
className={classes.form}
noValidate
>
<Grid
container
spacing={2}
>
<Grid
item
xs={3}
/>
<Grid
item
xs={6}
>
<TextField
autoComplete="username"
className={`form-control ${usernameError ? 'is-invalid' : ''}`}
fullWidth
id="username"
label="Enter Username"
margin="normal"
name="username"
onBlur={validateUsername}
onChange={e => setUsername(e.target.value)}
required
value={username}
variant="outlined"
/>
<div className={classes.invalidFeedback}>{usernameError}</div>
</Grid>
<Grid
item
xs={3}
/>
<Grid
item
xs={3}
/>
<Grid
item
xs={6}
>
<TextField
autoComplete="current-password"
className={`form-control ${passwordError ? 'is-invalid' : ''}`}
fullWidth
id="password"
label="Password"
margin="normal"
name="password"
onBlur={validatePassword}
onChange={e => setPassword(e.target.value)}
required
type="password"
value={password}
variant="outlined"
/>
<div className={classes.invalidFeedback}>{passwordError}</div>
</Grid>
<Grid
item
xs={3}
/>
<Grid
item
xs={3}
/>
<Grid
item
xs={3}
>
<Button
className={classes.submit}
color="primary"
fullWidth
onClick={handleSubmit}
type="submit"
variant="contained"
>
Sign In
</Button>
<Grid
item
xs={3}
/>
</Grid>
</Grid>
<Grid container>
<Grid
item
xs={3}
/>
<Grid
item
xs={3}
>
<Link
className={classes.link}
to={`${process.env.PUBLIC_URL}/passwordreset`}
variant="body2"
>
<Button
className={classes.submit}
color="primary"
fullWidth
type="submit"
variant="text"
>
Forgot Password
</Button>
</Link>
</Grid>
<Grid item>
<Link
className={classes.link}
to={`${process.env.PUBLIC_URL}/signup`}
variant="body2"
>
<Button
className={classes.submit}
color="primary"
fullWidth
type="submit"
variant="text"
>
New User?
</Button>
</Link>
</Grid>
</Grid>
<Box mt={5}>
<SigninTrouble />
</Box>
</form>
</div>
</MuiThemeProvider>
</Grid>
</Grid>
);
}
答案 0 :(得分:0)
要使用类型为commit的按钮,必须将其嵌套在html表单标记中,并使用onsubmit属性处理提交。 Onother选项是将onClick事件处理程序攻击到您的按钮,并使您的提交逻辑在那里。
答案 1 :(得分:0)
由于您使用的是Form,因此您需要使用表单而不是按钮来处理Submit方法。因为您的按钮类型为Submit,它会触发表单中的onSubmit事件。
<form onSubmit={handleSubmit}>
<button type="submit"></button>
</form>
如果要进行异步调用,则需要停止表单的正常事件周期。
const handleSubmit = (event) => {
// stop redirect
event.preventDefault();
console.log('testing button');
// here you can make your async call
}
答案 2 :(得分:0)
这是一个非常简单的示例:
import React, {useEffect, useState} from 'react';
function Example(props) {
function clickHandler() {
alert('hi');
}
return (
<div>
<button onClick={clickHandler}>Click here</button>
</div>
);
}
export default Example;