ADO中SQL Server 2008的datetime的等效数据类型是什么?

时间:2011-05-25 16:08:52

标签: sql-server-2008 ado

SQL Server 2008中的datetime数据类型支持毫秒。

我正在尝试执行一个接受datetime参数的存储过程,其中带有一个毫秒的arg作为输入/输出值。

我无法将传入的字符串转换为datetime值的方法。当我没有传入毫秒值时,转换正确。

我在下面的方法中看到转换问题。

Set objpara2 = objCom.CreateParameter("datetime", adDate, adParamInputOutput, , "2011-01-01 11:01:01.123")

ADO中SQL Server 2008的datetime的等效数据类型是什么?

以下是完整的代码段:

CREATE PROCEDURE [dbo].[TestProc] @time1 time, @datetime datetime output
as
begin
    SET NOCOUNT ON;
    select @datetime = datetime from ALLTimeTypes where time = @time1;
end

Private Sub Command1_Click()
    Dim objCon As ADODB.connection
    Dim objCom As ADODB.command
    Dim objPara As ADODB.Parameter
    Dim objpara2 As ADODB.Parameter
    Dim objRS As ADODB.Recordset
    Dim k As Integer

    Set objCon = New ADODB.connection
    Set objCom = New ADODB.command

    objConConnectionString = "Provider=SQLNCLI10;" _
         & "Data Source=ES-89W87BS;" _
         & "Database=MASTER;" _
         & "Integrated Security=SSPI;" _
         & "DataTypeCompatibility=80;" _
         & "User ID=sa;" _
         & "Password=<redacted>;"

    objCon.ConnectionString = objConConnectionString
    objCon.Open        
    MsgBox "Connection opened"

    With objCom
        .CommandText = "TestProc"     'Name of the stored procedure
        .CommandType = adCmdStoredProc  'Type : stored procedure
        .ActiveConnection = objCon.ConnectionString
    End With

    Set objPara = objCom.CreateParameter("time1", adVarChar, adParamInput, 50, "02:02:02.3456123")
    Set objpara2 = objCom.CreateParameter("datetime", adDate, adParamInputOutput, , "2011-01-01 11:01:01")

    objCom.Parameters.Append objPara
    objCom.Parameters.Append objpara2

    Set objRS = objCom.Execute        
    objRS.Open
    Do While Not objRS.EOF
        For k = 0 To objRS.Fields.Count - 1
            Debug.Print objRS(k).Name & ": " & objRS(k).Value
        Next
        objRS.MoveNext
    Loop        
    ...

3 个答案:

答案 0 :(得分:2)

根据thisadDBTimeStamp

答案 1 :(得分:2)

显然ADO正在消除毫秒。 http://support.microsoft.com/kb/246438

我没有尝试过这个,但我认为您应该将存储过程中参数的数据类型更改为varchar(23)并使用类似于'2011-05-17T10:18:54.293'的字符串参数。

答案 2 :(得分:1)

在日期和时间组件之间的字符串值中包含T时会发生什么情况?
(如2011-01-01T11:01:01.123

Set objpara2 = objCom.CreateParameter("datetime", adDate, adParamInputOutput,,
 "2011-01-01T11:01:01.123")