当“ takeUntil”工作时,我需要做最后的动作,然后进一步发送该数据,但是我无法确切知道takeUntil何时完成工作。 谢谢大家。
ngOnInit(): void {
const thumb = document.getElementById("thumb");
const track: HTMLElement = document.getElementById("track");
const activeTrack = document.getElementById("active-track");
const mouseUp = fromEvent(document, "mouseup");
const mouseMove = fromEvent(document, "mousemove").pipe(
map((item) => this.mouseEventToCoordinate(item, track))
);
const activeTrackClick = fromEvent(activeTrack, "click").pipe(
map((item) => this.mouseEventToCoordinate(item, track))
);
const trackClick = fromEvent(track, "click").pipe(
map((item) => this.mouseEventToCoordinate(item, track))
);
const mouseDown = fromEvent(thumb, "mousedown");
mouseDown
.pipe(
switchMap(() => mouseMove),
merge(trackClick, activeTrackClick),
takeUntil(mouseUp),
repeat()
)
.subscribe((item: { trackWidth: number; position: number }) => {
const newX = (item.position / item.trackWidth) * 100;
activeTrack.style.width = (newX + 1).toString() + "%";
thumb.style.left = newX.toString() + "%";
if (item === "Done") {
// Do somethings
}
});
}
答案 0 :(得分:0)
takeUntil
在此之前完成源Observable。这意味着我们可以利用完成。 repeat
再次开始完成。因此,我们可以执行以下操作:
mouseDown
.pipe(
switchMap(() => mouseMove),
merge(trackClick, activeTrackClick),
takeUntil(mouseUp),
tap({ complete: () => doSomething() }), // This will execute when mouseUp emits and takeUntil completes source Observable
repeat(),
)
...