Question

我有一个查询

SELECT date, SUM(cimpression) AS cimp, SUM(cclick) AS cclick 
FROM stdaily 
WHERE date BETWEEN :start AND :end 
AND (id = 21 AND id = 32 AND id = 12 AND id = 33)
GROUP BY date
ORDER BY date ASC;

此查询只需返回id等于21,32,12和33的结果，但返回的结果不包含那些特定的ID，不确定究竟是什么错误？有什么建议吗？

Answer 1

我认为您正在寻找的是：

SELECT date,SUM(cimpression) AS cimp, SUM(cclick) AS cclick
FROM stdaily
WHERE date BETWEEN :start AND :end 
AND id in (21, 32, 12, 33) 
GROUP BY date 
ORDER BY date ASC;

这将返回结果，其中包含in括号中包含的任何ID。

Answer 2

您的查询不正确，因为ID不能与所有这些值同时出现：

id = 21 AND id = 32 AND id = 12 AND id = 33

之前的条件失败，结果为NULL。

试试这个：

id = 21 OR id = 32 OR id = 12 OR id = 33

Answer 3

id = 21 AND id = 32 AND id = 12 AND id = 33

应该是

id = 21 OR id = 32 OR id = 12 OR id = 33

Answer 4

你没有指明他应该检查那些id的位置，你传递id的方式也是错误的

WHERE date BETWEEN :start AND :end AND (id = 21 AND id = 32 AND id = 12 AND id = 33 )

应该是这样的：

SELECT date,SUM(cimpression) AS cimp,SUM(cclick) AS cclick 
FROM stdaily 
WHERE date BETWEEN :start AND :end AND id IN (21, 32, 12, 33 ) 
GROUP BY date 
ORDER BY date ASC

Answer 5

我不知道您的数据是如何构建的，但我很惊讶这会返回任何结果。如何将id分别为21和32？例如，如果我使用

SELECT * FROM users WHERE 1=1 AND (id = 10 AND id = 11);

即使有ids 10和11的用户，我也不会得到结果。

你应该使用OR或更好的IN（21,32,12,33）

mySql返回不正确的结果

5 个答案: