Question

具有词典列表：

list_dict = [['key1', {'subkey1': 0}],
             ['key1', {'subkey2': 2}],
             ['key1', {'subkey5': 5}],
             ['key2', {'subkey2': 4}],
             ['key2', {'subkey1': 8}],
             ['key1', {'sybkey5': 10}]]

如何将list_dict转换为整洁的字典，如下所示？

{'key1': {'subkey1': 0, 'subkey2': 2, 'subkey5': 5},
 'key2': {'subkey2': 4, 'subkey1': 8, 'sybkey5': 10}}

Answer 1

以下方法应该起作用：

d = dict()
for item in list_dict:
    d.setdefault(item[0], {}).update(item[1])

来自Python 3 Documentation：

setdefault（key [，default]）

如果key在字典中，则返回其值。如果不是，请插入具有默认值的密钥，然后返回默认值。默认默认为无。

Answer 2

您可以使用collections.defaultdict：

from collections import defaultdict


list_dict = [['key1', {'subkey1': 0}],
             ['key1', {'subkey2': 2}],
             ['key1', {'subkey5': 5}],
             ['key2', {'subkey2': 4}],
             ['key2', {'subkey1': 8}],
             ['key1', {'sybkey5': 10}]]

d = defaultdict(dict)

for k, v in list_dict:
    d[k].update(v)
d

输出：

defaultdict(dict,
            {'key1': {'subkey1': 0, 'subkey2': 2, 'subkey5': 5, 'sybkey5': 10},
             'key2': {'subkey2': 4, 'subkey1': 8}})

或者您可以使用dict.setdefault，它有点慢：

d = {}
for k, v in list_dict:
    d.setdefault(k, {}).update(v)

输出：

{'key1': {'subkey1': 0, 'subkey2': 2, 'subkey5': 5, 'sybkey5': 10},
 'key2': {'subkey2': 4, 'subkey1': 8}}

Answer 3

这有效：

//First create a 'Driver' instance.
var driver = GraphDatabase.Driver("bolt://localhost:7687", AuthTokens.Basic("neo4j", "neo"), Config.Builder.WithEncryptionLevel(EncryptionLevel.None).ToConfig());

//Pass that driver to the BoltGraphClient
var bgc = new BoltGraphClient(driver);

//Connect.
bgc.Connect();

Answer 4

常规方法

new_dict = {}
for i in list_dict:
    if i[0] in new_dict.keys():
            new_dict[i[0]].update(i[1])
    else:
            new_dict[i[0]]=i[1]

从字典键，子键和值的列表构造字典

4 个答案: