如何创建具有三种颜色的自定义颜色图？

Question

我想使用Matplotlib创建具有三种颜色（红，白，蓝）的自定义颜色图。

我知道如何创建具有两种颜色的自定义颜色图。从红色到蓝色：

import numpy as np
from matplotlib.colors import ListedColormap
N = 1024
vals = np.zeros((N, 4))
vals[:, 0] = np.linspace(1.0, 0.0, N) # red
vals[:, 2] = np.linspace(0.0, 1.0, N) # blue
vals[:, 3] = 1.0
my_cmap = ListedColormap(vals)

但是如何在红色和蓝色之间添加白色？

Answer 1

我使用了来自matplotlib文档的经过修改的代码

import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
from matplotlib.colors import ListedColormap

def plot_examples(colormaps):
    """
    Helper function to plot data with associated colormap.
    """
    np.random.seed(19680801)
    data = np.random.randn(30, 30)
    n = len(colormaps)
    fig, axs = plt.subplots(1, n, figsize=(n * 2 + 2, 3),
                            constrained_layout=True, squeeze=False)
    for [ax, cmap] in zip(axs.flat, colormaps):
        psm = ax.pcolormesh(data, cmap=cmap, rasterized=True, vmin=-4, vmax=4)
        fig.colorbar(psm, ax=ax)
    plt.show()

# Red, Green, Blue
N = 256
vals = np.ones((N, 4))
# Red stays constant until middle of colormap all other channels increas
# to result in white
# from middle of colormap we decrease to 0, 0, 255 which is blue
vals[:, 0] = np.concatenate((np.linspace(1, 1, N//2), np.linspace(1, 0, N//2)), axis=None)
vals[:, 1] = np.concatenate((np.linspace(0, 1, N//2), np.linspace(1, 0, N//2)), axis=None)
vals[:, 2] = np.concatenate((np.linspace(0, 1, N//2), np.linspace(1, 1, N//2)), axis=None)
newcmp = ListedColormap(vals)

plot_examples([newcmp])

此脚本的输出类似于以下内容

Answer 2

您可以仅在ListedColormap中指定颜色，如下所示：

import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
from matplotlib.colors import ListedColormap

# make something to plot
x = np.linspace(0, 10, 400)
y = np.linspace(0, 10, 400)
xv, yv = np.meshgrid(x, y)
z = np.sin(xv*yv)

# make the color map:
cmp = ListedColormap(['red', 'white', 'blue'])

# do the plot
plt.pcolormesh(z, cmap=cmp)