我有两个请求具有相同的对象结果(“数据”)。我将得到两个响应并将所有响应放入数组(“ Data []”)。例子:
为我服务:
getData1(): Observable<Data> {
return this.http
.get<Data>(`${url}/data`):
}
getData2(): Observable<Data> {
return this.http
.get<Data>(`${url}/data`):
}
如何获取两种方法的结果并将所有内容都放入组件的data []中?
更新解决方案
服务
getData1(): Observable<Data> {
return this.http
.get<Data>(`${url}/data`):
}
getData2(): Observable<Data> {
return this.http
.get<Data>(`${url}/data`):
}
getDatas(): Observable<GetData[]> {
return forkJoin([this.getData1(), this.getData2()]);
}
组件
getDatas: GetData[];
ngOnInit() {
this.dataService.getDatas().subscribe(x => this.getDatas= x);
}
我可以在* ngFor =“让数据中的数据进行循环”
正在工作
答案 0 :(得分:2)
使用function [ acf ] = corrFFT(samplesMat,denomType,mu)
% Adaptation of inbuilt function autocorr to allow for multiple
% realisations, known mean and variable denominator.
%
% Input:
% samplesMat - nx by nSamples matrix of realisations
% denomType (optional) - 'cnst' or 'var'
% mu (optional) - if true mean is known
if nargin < 2
denomType = 'cnst';
end
if nargin < 3
mu = mean(mean(samplesMat));
end
[nx,~] = size(samplesMat);
nFFT = 2^(nextpow2(nx)+1);
F = fft(samplesMat-mu,nFFT);
F = F.*conj(F);
acf = ifft(mean(F,2));
acf = acf(1:nx);
if strcmp(denomType,'var')
acf = (nx./[nx:-1:1]').*acf;
end
acf = acf./acf(1);
acf = real(acf);
end
如下:
ForkJoin
这将以 getData(): Observable<Data[]> {
const req = [];
req.push(this.http.get<Data>(url_1));
req.push(this.http.get<Data>(url_2));
return forkJoin(req);
}
的形式返回响应,其中将提供两个网址的响应