Laravel-如何根据条件显示创建按钮

Question

在Laravel-5.8应用程序中，我只想在leave_status为0或所选雇员的行不存在时使创建按钮可见。

leave_status，可以具有以下任意一个值0、1、2、3、4

控制器：

public function index()
{
    try {  
        $userCompany    = Auth::user()->company_id;
        $userID         = Auth::user()->id;
        $userEmployee = Auth::user()->employee_id;
        $render=[]; 
        $leavetypes = HrLeaveType::where('company_id', $userCompany)->get();
        $leaverequests = HrLeaveRequest::where('employee_id', $userEmployee)->where('company_id', $userCompany)->whereYear('created_at', date('Y'))->get();
        $incompleteCount = $leaverequests->filter(function($item) {
            return ($item->leave_status == 0);
        })->count(); 
        return view('service.leave_requests.index')->with(['leaverequests' => $leaverequests, 'incompleteCount' => $incompleteCount]);
    } catch (Exception $exception) {
        Session::flash('error', 'Action failed! Please try again');
        return back();
    }           
}

查看：

@if ($incompleteCount)
    <div style="margin-bottom: 10px;" class="row">
        <div class="col-lg-12">
            <a class="btn btn-info" href="{{ route("service.leave_requests.create") }}">
                {{ trans('global.add') }} Leave Request
            </a>
        </div>
    </div>
@endif

这仅在行中有数据时有效。但是当表为空时，它将隐藏按钮。

对于选定的员工，如何仅在表中没有数据且leave_status为0时使按钮可见？

谢谢