所以我有2个组件:Button和App。 Button组件从数组映射一组按钮,并在App父级中调用。现在,当我在Button组件中单击一个按钮时,我希望它将该特定的ID及其名称返回给父组件,以便可以在应用程序中对其进行设置。
这是我的代码:
App.JS:
import React from "react";
import logo from "./logo.svg";
import "./App.css";
import Button from "./Button.js";
class App extends React.Component {
constructor() {
super();
this.state = {
displayTop: "test",
displayBot: 0,
};
}
render() {
return (
<div id="container">
<div id="displayTop">{this.state.displayTop}</div>
<div id="display">{this.state.displayBot}</div>
<Button />
</div>
);
}
}
export default App;
Button.JS
import React from "react";
import "./Button.css";
const buttonData = [
{ id: "clear", name: "AC" },
{ id: "divide", name: "/" },
{ id: "multiply", name: "*" },
{ id: "seven", name: "7" },
{ id: "eight", name: "8" },
{ id: "nine", name: "9" },
{ id: "subtract", name: "-" },
{ id: "four", name: "4" },
{ id: "five", name: "5" },
{ id: "six", name: "6" },
{ id: "add", name: "+" },
{ id: "one", name: "1" },
{ id: "two", name: "2" },
{ id: "three", name: "3" },
{ id: "equals", name: "=" },
{ id: "zero", name: "0" },
{ id: "decimal", name: "." },
];
class Button extends React.Component {
constructor() {
super();
}
render() {
const info = buttonData.map((info) => (
<button id={info.id}>{info.name}</button>
));
return info;
}
}
export default Button;
任何帮助将不胜感激!
谢谢!
答案 0 :(得分:1)
您可以将点击处理程序作为道具从父组件传递到Button
组件。例如,onClick
。
class App extends React.Component {
constructor() {
super();
this.state = {
displayTop: "test",
displayBot: 0,
};
}
handleClick = (id, name) => {
console.log('you just clicked', { id, name });
}
render() {
return (
<div id="container">
<div id="displayTop">{this.state.displayTop}</div>
<div id="display">{this.state.displayBot}</div>
<Button onClick={this.handleClick} />
</div>
);
}
}
并在传递要作为参数传递的数据时调用处理程序函数。
class Button extends React.Component {
constructor() {
super();
}
render() {
const { onClick } = this.props;
const info = buttonData.map((info) => (
<button id={info.id} onClick={() => onClick(info.id, info.name)}>{info.name}</button>
));
return info;
}
}
答案 1 :(得分:0)
您必须从#
组件传递道具,然后将其用于按钮的每个case msg => stash()
...
unstashAll()
context.become(active(file))
属性。
App
然后在Button组件中:
onClick