Question

这是一些php分页代码，它可以顺利运行。

        $rst =  mysql_query($qry) or die(mysql_error());
        $numrows    =   mysql_num_rows($rst);
        $qry         .= " limit $starting, $recpage";
        $this->result   =   mysql_query($qry) or die(mysql_error());
        $next       =   $starting+$recpage;
        $var        =   ((intval($numrows/$recpage))-1)*$recpage;
        $page_showing   =   intval($starting/$recpage)+1;
        $total_page =   ceil($numrows/$recpage); 



    $norepeat = 4;
    $j = 1;
    for($i=$page_showing; $i>1; $i--){
        $fpreviousPage = $i-1;
        $pagee = ceil($fpreviousPage*$recpage)-$recpage;
        $anch = "<a href='#' >$fpreviousPage</a>".$anch;
        if($j == $norepeat) break;
        $j++;
    }
    $anc .= $anch;  // last 4

    $anc .= $page_showing;   //current page

    $j = 1;
    for($i=$page_showing; $i<$total_page; $i++){
        $fnextPage = $i+1;
        $pagee = ceil($fnextPage*$recpage)-$recpage;
        $anc .= "<a href='#' >$fnextPage</a>"; // next 4
        if($j==$norepeat) break;
        $j++;
    }

(1) | 2 | 3 | 4 | 5   // (1) as current page
2 | 3 | 4 | 5 | (6) | 7 | 8 | 9 | 10  // (6) as current page
12 | 13 | 14 | 15 | (16) // (16) as current page, the last page

现在，如何修改代码，以便显示如下：

(1) | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9  // (1) as current page
2 | 3 | 4 | 5 | (6) | 7 | 8 | 9 | 10  // (6) as current page
8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | (16) // (16) as current page, the last page

将显示至少9页的分页。

如果页面总数小于9，仍然需要避免

(1) | 2 | 3 | 4 | 5 | 6 | 7 // (1) as current page, 7 pages all, show max 7, not 9.

感谢。

Answer 1

$norepeat = 9;

然后

 $j = 1;
    for($i=$page_showing; $i<$total_page; $i++){
        $fnextPage = $i+1;
        $pagee = ceil($fnextPage*$recpage)-$recpage;
        $anc .= "<a href='#' >$fnextPage</a>"; // next 4
      if($totalpage>=9){ if($j==$norepeat) break;}else { if($j==$totalpage) break;}
        $j++;
    }

修改分页脚本以显示最多9个页面链接

1 个答案: