我正在尝试从flutter中的函数返回Future对象，我必须在数据库查询块中添加return语句，无法从外部访问它，但是出现此错误{{ 1}}，因为期望在函数的末尾找到一个return语句，如果完整的示例在这里，则为：
Function has a return type of 'Future<Station>' but doesn't end with a return statement flutter每当我尝试在函数末尾添加 Future<Station> gettingStationData(String stationName) async {
var databasesPath = await getDatabasesPath();
String path = join(databasesPath, 'main.db');
Database database = await openDatabase(path, version: 1);
database.transaction((tnx) async {
List<Map> stationQuery = await tnx.rawQuery(
"SELECT * FROM Station WHERE stationName = ?", [stationName]);
Station station = Station(
key: stationQuery[0]['key'],
stationName: stationQuery[0]['stationName'],
cityName: stationQuery[0]['cityName'],
stationLatitude: stationQuery[0]['stationLatitude'],
stationLongitude: stationQuery[0]['stationLongitude']);
return station;
});
}
时，都会给我return station;错误。每当我尝试访问该函数时，它都会返回unresolved reference。有什么帮助吗？
答案 0 :(得分：2)
您需要返回database.transaction(...)返回的内容。
return database.transcation((tnx) async { ...