Question

我是Spring Boot的新手，我正在为基本实践编写CRUD操作，这是我的代码。

DemoApplication.java：

 package com.example.controller;
 import org.springframework.boot.SpringApplication;
 import org.springframework.boot.autoconfigure.SpringBootApplication;

 @SpringBootApplication
  public class DemoApplication {

    public static void main(String[] args) {
    SpringApplication.run(DemoApplication.class, args);
  }

}

User.java

   package com.example.model;

  public class User {
   String userName;
  String password;

public String getUserName() {
    return this.userName;
}

public void setUserName(String userName) {
    this.userName = userName;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}

}

UserServices.java：

 package com.example.services;
 import com.example.model.User;
 import org.springframework.stereotype.Repository;
 import org.springframework.stereotype.Service;

 @Repository
 public interface UserServices {
     public String loginService(User user);
 }

UserServiceImplementatioin.java：

package com.example.serviceimplementation;
import com.example.model.User;
import com.example.services.UserServices;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
@Service
public class UserServiceImplementation implements UserServices {
    public String loginService(User user) {
     if(user.getUserName().equals("demouser") && user.getPassword().equals("demopass")) {
        return "Login successfully";
     }
    return "Invalid Username and password";

    }
 }

ServiceController.java：

  package com.example.controller;
  import com.example.services.UserServices;
  import org.springframework.beans.factory.annotation.Autowired;
  import org.springframework.stereotype.Service;
  import org.springframework.web.bind.annotation.*;
  import com.example.model.User;

 @RestController
 @RequestMapping(value="/askmeanything")
  public class ServiceController {
  @Autowired
  private UserServices userServices;

  public UserServices getUserServices() {
    return userServices;
  }

  public void setUserServices(UserServices userServices) {
    this.userServices = userServices;
  }

 @CrossOrigin(origins = "*")
 @RequestMapping(value = "/login", method = RequestMethod.POST)
  public String getMsg(@RequestBody User user) throws  Exception {
    return userServices.loginService(user);
  }
}

上面的代码给了我错误 com.example.controller.ServiceController中的字段userServices需要一个类型为'com.example.services.UserServices'的bean。

Answer 1

这是因为您的DemoApplication是在以下软件包com.example.controller中定义的。因此，默认情况下，Spring将仅扫描该程序包及其外观。例如。 com.example.controller.something。它不会在父程序包中扫描。

要么将DemoApplication移动到父程序包，要么必须为组件扫描指定正确的程序包。

@SpringBootApplication(scanBasePackages={"com.example"})

我建议将类移到父包，然后让spring boot发挥作用。

春季启动：找不到bean

1 个答案: