Question

我制作了一个名为clear的脚本。该脚本可以正常工作。

但是我的清除脚本如何跳过频道中的固定消息？

这是我的脚本：


module.exports.run = async (bot, message, args) => {


    if (message.deletetable) {
        message.delete(); 
    }

    // Member doesn't have permission
    if (!message.member.hasPermission("MANAGE_MESSAGES")) {
        return message.channel.send("You can't delete messages...") // .then(m => m.delete(5000));
    }

    // Check if args[0] is a number
    if (isNaN(args[0]) || parseInt(args[0]) <= 0) {
        return message.channel.send("Yeah... That's not a number? I also can't delete 0 messages by the way.") // .then(m => m.delete(5000));

    }

    // Maybe the bot can't delete messages
    if (!message.guild.me.hasPermission("MANAGE_MESSAGES")) {
        return message.channel.send("Sorry... I can't delete messages.") // .then(m => m.delete(5000));
    }

    let deleteAmount;

    if (parseInt(args[0]) > 100) {
        deleteAmount = 100;
    } else {
        deleteAmount = parseInt(args[0]);
    }

    message.channel.bulkDelete(deleteAmount, true)
        .then(deleted => message.channel.send(`I deleted \`${deleted.size}\` messages.`))
        .catch(err => message.channel.send(`Something went wrong... ${err}`));
}   


module.exports.help = {
  name: "clear"
}

我希望有人可以帮助我，因为这将是我清晰脚本的不错补充。

Answer 1

获取通道中的所有消息，然后固定消息，对filter进行比较，仅保留非固定消息，然后删除这些消息。

client.on("message", async message => {
  if (message.author.bot) return;

  if (message.content === "/bulk") {
    const allMessages = await message.channel.messages.fetch()
    const deletable = allMessages.filter(message => !message.pinned)
    await message.channel.bulkDelete(deletable, true)
  }
});

bot清除脚本如何跳过固定的消息？

1 个答案: