传递路径作为参数时，出现“错误：无法将'std :: __ cxx11 :: string * {aka std :: __ cxx11 :: basic_string <char> *}'转换为'const char *'错误

Question

我是编程新手。我想从默认安装的目录访问所有目录和子目录，但是遍历该文件夹失败，这里我将路径传递给常量char。下面是代码

using namespace std;


int reading(const char *d_path)
{
    cout<<"In Reading"<<endl;

    /*bfs::path pathSource("c:\\Program Files\\");*/
    struct stat info; //

    DIR *dir;
    struct dirent *ent;
    dir= opendir (d_path);
    cout<<dir<<endl;
  if ((dir = opendir (d_path)) != NULL)
  {
      cout<<"in IF"<<endl;
       while ((ent = readdir (dir)) != NULL)
       {
          if (ent->d_name[0] != NULL)
          {
              cout<<"New"<<endl;
              string path = string (d_path) + string(ent->d_name) + '\\' ;
              cout<< "Entry = "<<path<<endl;
              stat (path,&info);
              if(S_ISDIR(info.st_mode))
              {
                  reading(path);
              }


          }
       }
       closedir (dir);
  }
  /* print all the files and directories within directory */

 else
    {
  /* could not open directory */
      perror ("");

    }

return 0;
}

Answer 1

使用string::c_str()之类的stat(path.c_str())方法将C ++字符串转换为C字符串。

有关更多信息，请参见http://cplusplus.com/reference/string/string/c_str/。