Question

我有如下代码，其中我过滤出比2天大的日期，并使其变粗并更改颜色。

在这种情况下，我还想将警告替换为失败，因为发现日期早于2天。

任何人都可以通过下面的代码来帮助我们实现这一目标。

import re
from datetime import datetime
ht ="""<tr>
<td>32356</td>
<td>cfra03</td>
<td>04-07-2020</td>
<td>Ssv</td>
<td>Warning</td>
</tr>
<tr>
<td>32367</td>
<td>c017</td>
<td>04-08-2020</td>
<td>SDR</td>
<td>Completed</td>
</tr>
<tr>
<td>29451</td>
<td>c10</td>
<td>04-05-2020</td>
<td>SR</td>
<td>Warning</td>
</tr>
"""

date_var = re.findall(r"[\d]{2}-[\d]{2}-[\d]{4}", ht)
for s in date_var:
    element_date = datetime.strptime(s, "%m-%d-%Y")
    if (datetime.now() - element_date).days > 2:
        ht = ht.replace(s, '<b><font color="#ff0000">'+s+'</font></b>')
print (ht)

当前输出为-

<tr>
<td>32356</td>
<td>cfra03</td>
<td>04-07-2020</td>
<td>Ssv</td>
<td>Warning</td>
</tr>
<tr>
<td>32367</td>
<td>c017</td>
<td>04-08-2020</td>
<td>SDR</td>
<td>Completed</td>
</tr>
<tr>
<td>29451</td>
<td>c10</td>
<td><b><font color="#ff0000">04-05-2020</font></b></td>
<td>SR</td>
<td>Warning</td>
</tr>

输出应为-

<tr>
<td>32356</td>
<td>cfra03</td>
<td>04-07-2020</td>
<td>Ssv</td>
<td>Warning</td>
</tr>
<tr>
<td>32367</td>
<td>c017</td>
<td>04-08-2020</td>
<td>SDR</td>
<td>Completed</td>
</tr>
<tr>
<td>29451</td>
<td>c10</td>
<td><b><font color="#ff0000">04-05-2020</font></b></td>
<td>SR</td>
<td><b><font color="#ff0000">Failed</font></b></td>
</tr>
'''

Answer 1

此代码：

import re
from datetime import datetime
ht ="""<tr>
<td>32356</td>
<td>cfra03</td>
<td>04-07-2020</td>
<td>Ssv</td>
<td>Warning</td>
</tr>
<tr>
<td>32367</td>
<td>c017</td>
<td>04-08-2020</td>
<td>SDR</td>
<td>Completed</td>
</tr>
<tr>
<td>29451</td>
<td>c10</td>
<td>04-05-2020</td>
<td>SR</td>
<td>Warning</td>
</tr>
"""

result = []
rows = ht.split('<tr>')
for row in rows :
    date_var = re.findall(r"[\d]{2}-[\d]{2}-[\d]{4}", row, re.DOTALL)
    for s in date_var:
        element_date = datetime.strptime(s, "%m-%d-%Y")
        if (datetime.now() - element_date).days > 2:
            row = row.replace(s, '<b><font color="#ff0000">'+s+'</font></b>')
            row = row.replace( 'Warning', 'Failed') # or whatever
    result.append(row)

print ('<tr>'.join(result))

给出以下结果：

<tr>
<td>32356</td>
<td>cfra03</td>
<td>04-07-2020</td>
<td>Ssv</td>
<td>Warning</td>
</tr>
<tr>
<td>32367</td>
<td>c017</td>
<td>04-08-2020</td>
<td>SDR</td>
<td>Completed</td>
</tr>
<tr>
<td>29451</td>
<td>c10</td>
<td><b><font color="#ff0000">04-05-2020</font></b></td>
<td>SR</td>
<td>Failed</td>
</tr>

您可以根据需要在Failed周围添加HTML。

查找日期并替换单词-Python

1 个答案: