我有下面的代码(继续我之前的问题SQL How to list Columns in a Table as a Cursor Statement)
select
(select * from
(select Narrative
from OfficeClientLedger
where ptMatter=$Matter$ and ptTrans = 4)
as Disbursments for xml auto)
返回
<OFFICECLIENTLEDGER NARRATIVE="M0604/20 Cwm Taff NHS Trust Medical Records (C)"/><OFFICECLIENTLEDGER NARRATIVE="M0604/210 Dr Purby Medeical Records (C)"/><OFFICECLIENTLEDGER NARRATIVE="M0604.20 Orchid Cellmark tld Fee"/><OFFICECLIENTLEDGER NARRATIVE="M0604/20 Parsons Dowd Psychological Ltd Assessment Fees"/><OFFICECLIENTLEDGER NARRATIVE="M0604/20 Dr R Oretti Drug testing"/><OFFICECLIENTLEDGER NARRATIVE="M0604/20 Correction of MIssposting CQ 013524"/><OFFICECLIENTLEDGER NARRATIVE="M0604/20 Helen Blackler Assessment Fees (P) "/>
但是,我需要它给我一个列表,如
M0604 / 20 Cwm Taff NHS Trust Medical 记录(C)
M0604 / 210 Purby Medeical Records博士 (C)
M0604.20 Orchid Cellmark tld费
M0604 / 20 Parsons Dowd
M0604 / 20 R Oretti博士药物测试
M0604 / 20 MIsposting CQ的更正 013524
M0604 / 20 Helen Blackler评估 费用(P)
任何想法?感谢
答案 0 :(得分:1)
select
(select cast(Narrative as varchar(max))
from OfficeClientLedger
where ptMatter=$Matter$ and ptTrans = 4
as Disbursments for xml path(''), true)
答案 1 :(得分:0)
您可以使用XSL样式表更改从SQL Server检索的XML的格式。