我正在寻找一个很好的JS片段来将时间戳(例如来自Twitter API)转换为友好的用户友好相对时间(例如2秒前,一周前等)。
任何人都想分享一些他们喜欢的方法(最好不要使用插件)?
答案 0 :(得分:91)
如果你不过分关注准确性,那很容易。这个琐碎的方法有什么问题?
function timeDifference(current, previous) {
var msPerMinute = 60 * 1000;
var msPerHour = msPerMinute * 60;
var msPerDay = msPerHour * 24;
var msPerMonth = msPerDay * 30;
var msPerYear = msPerDay * 365;
var elapsed = current - previous;
if (elapsed < msPerMinute) {
return Math.round(elapsed/1000) + ' seconds ago';
}
else if (elapsed < msPerHour) {
return Math.round(elapsed/msPerMinute) + ' minutes ago';
}
else if (elapsed < msPerDay ) {
return Math.round(elapsed/msPerHour ) + ' hours ago';
}
else if (elapsed < msPerMonth) {
return 'approximately ' + Math.round(elapsed/msPerDay) + ' days ago';
}
else if (elapsed < msPerYear) {
return 'approximately ' + Math.round(elapsed/msPerMonth) + ' months ago';
}
else {
return 'approximately ' + Math.round(elapsed/msPerYear ) + ' years ago';
}
}
工作示例here。
您可能想要调整它以更好地处理奇异值(例如1 day
而不是1 days
),如果这让您感到困扰。
答案 1 :(得分:19)
以下是没有插件的Twitter时间的精确模仿:
function timeSince(timeStamp) {
var now = new Date(),
secondsPast = (now.getTime() - timeStamp.getTime()) / 1000;
if(secondsPast < 60){
return parseInt(secondsPast) + 's';
}
if(secondsPast < 3600){
return parseInt(secondsPast/60) + 'm';
}
if(secondsPast <= 86400){
return parseInt(secondsPast/3600) + 'h';
}
if(secondsPast > 86400){
day = timeStamp.getDate();
month = timeStamp.toDateString().match(/ [a-zA-Z]*/)[0].replace(" ","");
year = timeStamp.getFullYear() == now.getFullYear() ? "" : " "+timeStamp.getFullYear();
return day + " " + month + year;
}
}
要点https://gist.github.com/timuric/11386129
小提琴http://jsfiddle.net/qE8Lu/1/
希望它有所帮助。
答案 2 :(得分:5)
多田! Timeago:http://timeago.yarp.com/
哦,坚持下去 - 没有插件?那为什么呢?我想你可以打开插件文件并破解其中的内容。
答案 3 :(得分:4)
在Diego Castillo awnser's和timeago.js插件中启示,我为此编写了自己的vanilla插件。
Handlebars.RegisterHelper("formatDate", New HandlebarsHelper(Sub(w, c, p)
w.WriteSafeString("moment(" + p(0) + ").format(" + p(1) + ");")
End Sub))
Handlebars.RegisterHelper("formatPercent", New HandlebarsHelper(Sub(w, c, p)
If p(1) = 0 Then
w.WriteSafeString("0")
Else
w.WriteSafeString("Math.ceil(" + 100 * p(0) / p(1) + ");")
End If
End Sub))
var timeElement = document.querySelector('time'),
time = new Date(timeElement.getAttribute('datetime'));
timeElement.innerText = TimeAgo.inWords(time.getTime());
var TimeAgo = (function() {
var self = {};
// Public Methods
self.locales = {
prefix: '',
sufix: 'ago',
seconds: 'less than a minute',
minute: 'about a minute',
minutes: '%d minutes',
hour: 'about an hour',
hours: 'about %d hours',
day: 'a day',
days: '%d days',
month: 'about a month',
months: '%d months',
year: 'about a year',
years: '%d years'
};
self.inWords = function(timeAgo) {
var seconds = Math.floor((new Date() - parseInt(timeAgo)) / 1000),
separator = this.locales.separator || ' ',
words = this.locales.prefix + separator,
interval = 0,
intervals = {
year: seconds / 31536000,
month: seconds / 2592000,
day: seconds / 86400,
hour: seconds / 3600,
minute: seconds / 60
};
var distance = this.locales.seconds;
for (var key in intervals) {
interval = Math.floor(intervals[key]);
if (interval > 1) {
distance = this.locales[key + 's'];
break;
} else if (interval === 1) {
distance = this.locales[key];
break;
}
}
distance = distance.replace(/%d/i, interval);
words += distance + separator + this.locales.sufix;
return words.trim();
};
return self;
}());
// USAGE
var timeElement = document.querySelector('time'),
time = new Date(timeElement.getAttribute('datetime'));
timeElement.innerText = TimeAgo.inWords(time.getTime());
答案 4 :(得分:4)
当前(十二月18日)一个Stage 3 proposal,并且已经在Chrome 71中实现
const rtf = new Intl.RelativeTimeFormat('en', { numeric: 'auto' });
const millisecondsPerDay = 24 * 60 * 60 * 1000;
[
[3.14 , 'second' ],
[-15 , 'minute' ],
[8 , 'hour' ],
[-1 , 'day' ],
[3 , 'week' ],
[-5 , 'month' ],
[2 , 'quarter'],
[-42 , 'year' ],
[(new Date('9/22/2018') - new Date())/millisecondsPerDay,'day']
].forEach(d => console.log( rtf.format(d[0], d[1]) ));
Intl.RelativeTimeFormat 在 V8 v7.1.179 中默认可用 Chrome 71 。随着该API的广泛使用,您会发现 Moment.js,Globalize和date-fns之类的库 对硬编码CLDR数据库的依赖性,以本机相对 时间格式化功能,从而缩短了加载时间 性能,分析和编译时性能,运行时 性能和内存使用情况。
答案 5 :(得分:4)
const units = [
['year', 31536000000],
['month', 2628000000],
['day', 86400000],
['hour', 3600000],
['minute', 60000],
['second', 1000],
]
const rtf = new Intl.RelativeTimeFormat('en', { style:'narrow'})
const relatime = elapsed => {
for (const [unit, amount] of units) {
if (Math.abs(elapsed) > amount || unit === 'second') {
return rtf.format(Math.round(elapsed/amount), unit)
}
}
}
打高尔夫球192b
很有趣
const relatime = e=>{for(let[u,a]of Object.entries({year:31536e6,month:2628e6,day:864e5,hour:36e5,minute:6e4,second:1e3})){if(Math.abs(e)>a||a===1e3){return new Intl.RelativeTimeFormat('en',{style:'narrow'}).format(~~(e/a),u)}}}
我还在打高尔夫球时测试了功能版本:
const rtf = new Intl.RelativeTimeFormat('en', { style:'narrow'})
const relatime = Object.entries({year:31536e6,month:2628e6,day:864e5,hour:36e5,minute:6e4,second:1e3})
.reduce((f, [unit, amount]) => amount === 1e3
? f(elapsed => rtf.format(Math.round(elapsed/amount), unit))
: next => f(e => Math.abs(e) < amount
? next(elapsed)
: rtf.format(Math.round(elapsed/amount), unit)), _=>_)
好吧,我真的必须立即恢复工作...
答案 6 :(得分:2)
使用 Web API RelativeTimeFormat 结合 Typescript 实现 @vsync 和 @kigiri 方法。
const units: {unit: Intl.RelativeTimeFormatUnit; ms: number}[] = [
{unit: "year", ms: 31536000000},
{unit: "month", ms: 2628000000},
{unit: "day", ms: 86400000},
{unit: "hour", ms: 3600000},
{unit: "minute", ms: 60000},
{unit: "second", ms: 1000},
];
const rtf = new Intl.RelativeTimeFormat("en", {numeric: "auto"});
/**
* Get language-sensitive relative time message from Dates.
* @param relative - the relative dateTime, generally is in the past or future
* @param pivot - the dateTime of reference, generally is the current time
*/
export function relativeTimeFromDates(relative: Date | null, pivot: Date = new Date()): string {
if (!relative) return "";
const elapsed = relative.getTime() - pivot.getTime();
return relativeTimeFromElapsed(elapsed);
}
/**
* Get language-sensitive relative time message from elapsed time.
* @param elapsed - the elapsed time in milliseconds
*/
export function relativeTimeFromElapsed(elapsed: number): string {
for (const {unit, ms} of units) {
if (Math.abs(elapsed) > ms || unit === "second") {
return rtf.format(Math.round(elapsed / ms), unit);
}
}
return "";
}
答案 7 :(得分:1)
对于任何有兴趣的人,我最终创建了一个Handlebars助手来完成此任务。 用法:
{{#beautify_date}}
{{timestamp_ms}}
{{/beautify_date}}
助手:
Handlebars.registerHelper('beautify_date', function(options) {
var timeAgo = new Date(parseInt(options.fn(this)));
if (Object.prototype.toString.call(timeAgo) === "[object Date]") {
if (isNaN(timeAgo.getTime())) {
return 'Not Valid';
} else {
var seconds = Math.floor((new Date() - timeAgo) / 1000),
intervals = [
Math.floor(seconds / 31536000),
Math.floor(seconds / 2592000),
Math.floor(seconds / 86400),
Math.floor(seconds / 3600),
Math.floor(seconds / 60)
],
times = [
'year',
'month',
'day',
'hour',
'minute'
];
var key;
for(key in intervals) {
if (intervals[key] > 1)
return intervals[key] + ' ' + times[key] + 's ago';
else if (intervals[key] === 1)
return intervals[key] + ' ' + times[key] + ' ago';
}
return Math.floor(seconds) + ' seconds ago';
}
} else {
return 'Not Valid';
}
});
答案 8 :(得分:1)
存在日期时间插件,因为很难做到正确。这个video explaining date-time inconsistencies将为这个问题提供一些启示。
以上没有插件的解决方案都不正确。
使用日期和时间最好使用插件。在处理它的数百个插件中,我们使用Moment.js并且它正在完成这项工作。
从twitter API dcumentation我们可以看到他们的时间戳格式:
"created_at":"Wed Aug 27 13:08:45 +0000 2008"
我们可以使用Moment.js
解析它const postDatetime = moment(
"Wed Aug 27 13:08:45 +0000 2008",
"dddd, MMMM Do, h:mm:ss a, YYYY"
);
const now = moment();
const timeAgo = now.diff(postDatetime, 'seconds');
要指定diff
的首选时间单位,我们可以使用isSame
方法。例如:
if (now.isSame(postDatetime, 'day')) {
const timeUnit = 'days';
}
总的来说,构建类似的东西:
`Posted ${timeAgo} ${timeUnit} ago`;
请参阅插件的文档以了解处理相对时间(即:“多久以前?”)计算。
答案 9 :(得分:1)
答案 10 :(得分:1)
如果您需要多语言,并且不想像片刻那样添加大型图书馆。来自雅虎的intl-relativeformat这是一个很好的解决方案。
var rf = new IntlRelativeFormat('en-US');
var posts = [
{
id : 1,
title: 'Some Blog Post',
date : new Date(1426271670524)
},
{
id : 2,
title: 'Another Blog Post',
date : new Date(1426278870524)
}
];
posts.forEach(function (post) {
console.log(rf.format(post.date));
});
// => "3 hours ago"
// => "1 hour ago"
答案 11 :(得分:0)
您可以将machinepack-datetime用于此目的。它定义的API很简单明了。
tutorialSchema.virtual('createdOn').get(function () {
const DateTime = require('machinepack-datetime');
let timeAgoString = "";
try {
timeAgoString = DateTime.timeFrom({
toWhen: DateTime.parse({
datetime: this.createdAt
}).execSync(),
fromWhen: new Date().getTime()
}).execSync();
} catch(err) {
console.log('error getting createdon', err);
}
return timeAgoString; // a second ago
});
答案 12 :(得分:0)
对于Moment.js用户,它具有fromNow()函数,该函数从当前日期/时间返回“ x天”或“ x小时前”。
moment([2007, 0, 29]).fromNow(); // 4 years ago
moment([2007, 0, 29]).fromNow(true); // 4 years