Question

我试图使用XmlSerializer和SoapFormatter序列化一个对象，但我不能让输出看起来像这样：

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
 <soap:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Login xmlns="http://www.myfirm.com/2010/core/ConnectTypes">
  <UserLogin>
    <UserName>User</UserName>
    <Password>PW</Password>
    <Mandant>1</Mandant>
  </UserLogin>
</Login>

 </soap:Body>
</soap:Envelope>

我的课程：

[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
public partial class UserLoginType
{

    private string userNameField;

    private string passwordField;

    private int mandantField;

    /// <remarks/>
    public string UserName
    {
        get
        {
            return this.userNameField;
        }
        set
        {
            this.userNameField = value;
        }
    }

    /// <remarks/>
    public string Password
    {
        get
        {
            return this.passwordField;
        }
        set
        {
            this.passwordField = value;
        }
    }

    /// <remarks/>
    public int Mandant
    {
        get
        {
            return this.mandantField;
        }
        set
        {
            this.mandantField = value;
        }
    }
}

[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
public partial class LoginType
{

    private object itemField;

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("LoginToken", typeof(string))]
    [System.Xml.Serialization.XmlElementAttribute("UserLogin", typeof(UserLoginType))]
    public object Item
    {
        get
        {
            return this.itemField;
        }
        set
        {
            this.itemField = value;
        }
    }
}

有人可以帮忙吗？

Answer 1

记录SoapRequest尝试MessageInspector或启用Web.Config for Web Service登录。

Answer 2

通常，您不必像这样序列化我们的对象。您应该通过WSDL-url添加Web-Reference，并通过生成的代理类调用服务的方法

创建肥皂请求

2 个答案: