Question

我想从列表列表中生成不同的列表。参见示例

[['this', "isn't", 'working'], ['working', 'great'], ["isn't", 'working'], ['and'], ['great'], ['working', 'this', "isn't"]]

应该像

list1 = [['and'], ['great']]
list2 = [['working', 'great'], ["isn't", 'working']]
list3 = [['this', "isn't", 'working'],['working', 'this', "isn't"]]
like wise...list4 having 4 elements and so on.

，然后将它们转换为数据帧。但是目前，我想基于这些元素创建列表。如果可以提出一些想法，将会有所帮助。出于示例目的，在示例中显示了一个小列表，这将是一个大列表，因此可以理解一种有效的技术。

谢谢。

Answer 1

一种方法是定义一个defaultdict，并插入具有与子列表的长度相对应的键的元素，并通过键保留dict.values sorted：

from collections import defaultdict

d = defaultdict(list)

for subl in l:
    d[len(subl)].append(subl)

out = [d[i] for i in sorted(d)]

print(out)

[[['and'], ['great']],
 [['working', 'great'], ["isn't", 'working']],
 [['this', "isn't", 'working'], ['working', 'this', "isn't"]]]

根据列表中的元素数创建其他列表

1 个答案: