我有一个简单的问题,我不知道如何在Perl中解决。我知道如何从utf-8转换为GBK,例如,从e4b8ad
转换为d6d0
。但我不确定如何向后退,即给定d6d0
,我怎么知道e4b8ad
。
请赐教!非常感谢。
答案 0 :(得分:3)
当你有十六进制数字时,pack是你的朋友。以下是REPL会议。注意:
$ use Encode qw(decode encode); use Encode::HanExtra; use Devel::Peek qw(Dump);
$ 'e4b8ad'
e4b8ad # hex digits
$ pack('H*', 'e4b8ad')
中
$ Dump(pack('H*', 'e4b8ad'))
SV = PV(0x3657680) at 0x36b7188
REFCNT = 1
FLAGS = (PADTMP,POK,pPOK)
PV = 0x36c0768 "\344\270\255"\0 # octets of UTF-8 encoded data
CUR = 3
LEN = 8
$ decode('UTF-8', pack('H*', 'e4b8ad'))
中
$ Dump(decode('UTF-8', pack('H*', 'e4b8ad')))
SV = PV(0x326c3a0) at 0x36a50c8
REFCNT = 1
FLAGS = (TEMP,POK,pPOK,UTF8)
PV = 0x3698a48 "\344\270\255"\0 [UTF8 "\x{4e2d}"] # character string
CUR = 3
LEN = 8
$ encode('GB18030', decode('UTF-8', pack('H*', 'e4b8ad')))
"\xd6\xd0"
$ Dump(encode('GB18030', decode('UTF-8', pack('H*', 'e4b8ad'))))
SV = PV(0x36a2da0) at 0x36b6d98
REFCNT = 1
FLAGS = (TEMP,POK,pPOK)
PV = 0x36db3e8 "\326\320"\0 # octets of GB18030 encoded data
CUR = 2
LEN = 8
$ unpack('H*', encode('GB18030', decode('UTF-8', pack('H*', 'e4b8ad'))))
d6d0 # hex digits
答案 1 :(得分:1)
问题的答案是:
use Encode qw( from_to );
my $gbk = "\xD6\xD0";
from_to(my $utf8 = $gbk, 'GB18030', 'UTF-8'); # E4 B8 AD
或
use Encode qw( decode encode );
my $gbk = "\xD6\xD0";
my $utf8 = encode('UTF-8', decode('GB18030', $gbk)); # E4 B8 AD
但是,更正常的流程如下所示:
open(my $fh_in, '<:encoding(GB18030)', ...) or die ...;
open(my $fh_out, '>:encoding(UTF-8)', ...) or die ...;
while (<$fh_in>) {
...
print $fh_out ...;
...
}
必须为Encode安装Encode :: HanExtra才能找到编码。
答案 2 :(得分:0)
use Encode qw/encode decode/;
$utf8 = decode("euc-cn", $euc_cn); # ditto
您通常也可以在打开或关闭FD时指定编码,并执行必要的转换。
像魅力一样:
perl -e 'open(X,">","/tmp/x"); print X chr(0xd6).chr(0xd0);close(X)'
perl -mEncode -e 'open(X,"<","/tmp/x"); $x=<X>; print Encode::decode("euc-cn",$x);' > /tmp/xx