Question

我应该得到一个文件并扫描信息。当我尝试将其打印出来时，我扫描的大部分信息都会丢失或被切掉。这是我的代码：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

typedef struct profile {

    char gender;
    float soc;
    char name[20];
    char name2[20];
    int age;
    char job[20];
    float income;
    char M_hob[20];
    char m_hob[20];
    int height;
    int weight;
    char relig[20];
} PROFILE;

int main(void)
{

    int i, count;
    char file[30], ssn[10];
    FILE *fin;
    PROFILE members[50];

    printf("SSN: ");
    scanf("%s", ssn);
    printf("Name of file of records: ");
    scanf("%s", file);

    fin = fopen(file, "r");

    if ((fin == NULL)) {
        printf("Can't Open File");
        exit(1);
    }

    i = 0;
    while (fscanf(fin, "%c", &members[i].gender) != EOF) {

        fscanf(fin, "%f", &members[i].soc);
        fscanf(fin, "%s", members[i].name);
        fscanf(fin, "%s", members[i].name2);
        strcat(members[i].name, members[i].name2);
        fscanf(fin, "%d", &members[i].age);
        fscanf(fin, "%s", members[i].job);
        fscanf(fin, "%f", &members[i].income);
        fscanf(fin, "%s", members[i].M_hob);
        fscanf(fin, "%s", members[i].m_hob);
        fscanf(fin, "%d", &members[i].height);
        fscanf(fin, "%d", &members[i].weight);
        fscanf(fin, "%s", members[i].relig);
        fscanf(fin, "%c", &members[i].space);

        i++;
    }
    fclose(fin);

    count = i;
    for (i = 0; i <= count; i++) {
        printf("%c\n", members[i].gender);
        printf("%.0f\n", members[i].soc);
        printf("%s\n", members[i].name);
        printf("%d\n", members[i].age);
        printf("%s\n", members[i].job);
        printf("%.0f\n", members[i].income);
        printf("%s\n", members[i].M_hob);
        printf("%s\n", members[i].m_hob);
        printf("%d\n", members[i].height);
        printf("%d\n", members[i].weight);
        printf("%s\n", members[i].relig);
    }

    return 0;
}

我正在扫描的两段：

M
111223333
Rob Low
47
Actor
1000000
Dancing
Painting
63
165
Atheist

M
123456789
Bob Mitchell
77
Driver
25000
Baseball
Cooking
72
275
None

和打印出来的部分内容：

M
111223336
Rob
47
Actor
1000000
Dancing
Painting
63
165
Atheist

0
M
0
Bob
0
Mitchell
77
0
0
Driver
2
5000
Baseball
72
275
0
ne

正如你所看到的那样，第一个被完美扫描，但其余的都是错误的。

Answer 1

如果您必须使用fscanf()，请检查每个返回值。

担心循环前面的%c在第二个循环中获取换行符。

你最好将每一行读成一个大字符串，然后将sscanf()应用于它。这至少避免了对换行的混淆。（我不会用bargepole触摸scanf()或fscanf()因为他们处理换行符的方式 - 或者不是。）

代码未正确扫描所有内容

1 个答案: