我正在复制代码,并可能更改了 w3schools代码。 Dropdown 2 和 Dropdown 3 button
无效。
/* When the user clicks on the button,
toggle between hiding and showing the dropdown content */
function myFunction() {
document.getElementById("myDropdown").classList.toggle("show");
}
// Close the dropdown if the user clicks outside of it
window.onclick = function(e) {
if (!e.target.matches('.dropbtn')) {
var myDropdown = document.getElementById("myDropdown");
if (myDropdown.classList.contains('show')) {
myDropdown.classList.remove('show');
}
}
}
.navbar {
overflow: hidden;
background-color: #333;
font-family: Arial, Helvetica, sans-serif;
}
.navbar a {
float: left;
font-size: 16px;
color: white;
text-align: center;
padding: 14px 16px;
text-decoration: none;
}
.dropdown {
float: left;
overflow: hidden;
}
.dropdown .dropbtn {
cursor: pointer;
font-size: 16px;
border: none;
outline: none;
color: white;
padding: 14px 16px;
background-color: inherit;
font-family: inherit;
margin: 0;
}
.navbar a:hover, .dropdown:hover .dropbtn, .dropbtn:focus {
background-color: red;
}
.dropdown-content {
display: none;
position: absolute;
background-color: #f9f9f9;
min-width: 160px;
box-shadow: 0px 8px 16px 0px rgba(0,0,0,0.2);
z-index: 1;
}
.dropdown-content a {
float: none;
color: black;
padding: 12px 16px;
text-decoration: none;
display: block;
text-align: left;
}
.dropdown-content a:hover {
background-color: #ddd;
}
.show {
display: block;
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font-awesome/4.7.0/css/font-awesome.min.css">
</head>
<body>
<div class="navbar">
<div class="dropdown">
<button class="dropbtn" onclick="myFunction()">Dropdown 1
<i class="fa fa-caret-down"></i>
</button>
<div class="dropdown-content" id="myDropdown">
<a href="#">Link 1</a>
<a href="#">Link 2</a>
<a href="#">Link 3</a>
</div>
</div>
<div class="dropdown">
<button class="dropbtn" onclick="myFunction()">Dropdown 2
<i class="fa fa-caret-down"></i>
</button>
<div class="dropdown-content" id="myDropdown">
<a href="#">Link 1</a>
<a href="#">Link 2</a>
<a href="#">Link 3</a>
</div>
</div>
<div class="dropdown">
<button class="dropbtn" onclick="myFunction()">Dropdown 3
<i class="fa fa-caret-down"></i>
</button>
<div class="dropdown-content" id="myDropdown">
<a href="#">Link 1</a>
<a href="#">Link 2</a>
<a href="#">Link 3</a>
</div>
</div>
</div>
</body>
</html>
答案 0 :(得分:2)
问题是您的所有3个下拉菜单都具有相同的id
,这是不允许的。而且,由于所有3个按钮都使用相同的回调,并且该回调专门切换了已重用的id
的可见性,因此系统在找到第一个匹配元素时会停止(因为不应该有多个元素具有相同的{{ 1}})。
现实情况是,虽然看起来很简单,但首先使用id
会导致脆性代码无法缩放(如您所见),因此请避免使用id
并使用CSS类和HTML元素的层次结构作为查找元素的方法。
还有never use getElementsByClassName()
或inline HTML event attributes。
帮自己一个忙,众所周知,W3学校信息不完整,不准确或仅有明显的错误信息,请尽量远离。相反,您将从The Mozilla Developers Network (MDN)(JavaScript语言的管理者)那里获得更加全面和最新的信息。
有关详细信息,请参见以下评论:
id
// Set your events up in JavaScript, not with HTML event attributes
document.addEventListener("click", function(event) {
// Loop over all the menus
document.querySelectorAll(".dropdown-content").forEach(function(dd){
dd.classList.remove("show"); // Hide the menu
});
// If the clicked element was a button
if (event.target.classList.contains('dropbtn')) {
// Show just the menu that corresponds to the clicked button
event.target.nextElementSibling.classList.toggle("show");
}
});
.dropbtn {
background-color: #3498DB;
color: white;
padding: 16px;
font-size: 16px;
border: none;
cursor: pointer;
}
.dropbtn:hover, .dropbtn:focus {
background-color: #2980B9;
}
.dropdown {
position: relative;
display: inline-block;
}
.dropdown-content {
display: none;
position: absolute;
background-color: #f1f1f1;
min-width: 160px;
overflow: auto;
box-shadow: 0px 8px 16px 0px rgba(0,0,0,0.2);
z-index: 1;
}
.dropdown-content a {
color: black;
padding: 12px 16px;
text-decoration: none;
display: block;
}
.dropdown a:hover {background-color: #ddd;}
.show {display: block;}
答案 1 :(得分:1)
您必须以某种方式区分菜单。我使用了data-target
属性。另外,在显示之前,您需要隐藏所有可见菜单。关于按钮外观,只需根据自己的喜好更改.dropbtn
的css。
/* When the user clicks on the button,
toggle between hiding and showing the dropdown content */
function myFunction(el) {
var currentMenu = document.querySelector(".dropdown-content.show");
if (currentMenu) currentMenu.classList.toggle("show");
document.getElementById(el.dataset.target).classList.toggle("show");
}
// Close the dropdown if the user clicks outside of it
window.onclick = function(event) {
if (!event.target.matches('.dropbtn')) {
var dropdowns = document.getElementsByClassName("dropdown-content");
var i;
for (i = 0; i < dropdowns.length; i++) {
var openDropdown = dropdowns[i];
if (openDropdown.classList.contains('show')) {
openDropdown.classList.remove('show');
}
}
}
}
.dropbtn {
background-color: #3498DB;
color: white;
padding: 16px;
font-size: 16px;
border: none;
cursor: pointer;
}
.dropbtn:hover,
.dropbtn:focus {
background-color: #2980B9;
}
.dropdown {
position: relative;
display: inline-block;
}
.dropdown-content {
display: none;
position: absolute;
background-color: #f1f1f1;
min-width: 160px;
overflow: auto;
box-shadow: 0px 8px 16px 0px rgba(0, 0, 0, 0.2);
z-index: 1;
}
.dropdown-content a {
color: black;
padding: 12px 16px;
text-decoration: none;
display: block;
}
.dropdown a:hover {
background-color: #ddd;
}
.show {
display: block;
<div class="dropdown">
<button onclick="myFunction(this)" data-target="dropdown1" class="dropbtn">Dropdown 1</button>
<div id="dropdown1" class="dropdown-content">
<a href="#home">Home 1</a>
<a href="#about">About 1</a>
<a href="#contact">Contact 1</a>
</div>
</div>
<div class="dropdown">
<button onclick="myFunction(this)" data-target="dropdown2" class="dropbtn">Dropdown 2</button>
<div id="dropdown2" class="dropdown-content">
<a href="#home">Home 2</a>
<a href="#about">About 2</a>
<a href="#contact">Contact 2</a>
</div>
</div>
<div class="dropdown">
<button onclick="myFunction(this)" data-target="dropdown3" class="dropbtn">Dropdown 3</button>
<div id="dropdown3" class="dropdown-content">
<a href="#home">Home 3</a>
<a href="#about">About 3</a>
<a href="#contact">Contact 3</a>
</div>
</div>
答案 2 :(得分:1)
您可以使用 .nextElementSibling ==> https://developer.mozilla.org/en-US/docs/Web/API/NonDocumentTypeChildNode/nextElementSibling
以您的情况
const allButtons = document.querySelectorAll('button.dropbtn');
allButtons.forEach(btn=>
{
btn.onclick=()=>{
allButtons.forEach(btn_X=>
{
let divContent = btn_X.nextElementSibling
if ( btn===btn_X) divContent.classList.toggle('show')
else divContent.classList.remove('show')
})
}
})
// Close the dropdown if the user clicks outside of it
window.onclick =e=>
{
if (e.target.matches('.dropbtn')) return
allButtons.forEach(btn=>btn.nextElementSibling.classList.remove('show'))
}
.dropbtn {
background-color: #3498DB;
color: white;
padding: 16px;
font-size: 16px;
border: none;
cursor: pointer;
}
.dropbtn:hover, .dropbtn:focus {
background-color: #2980B9;
}
.dropdown {
position: relative;
display: inline-block;
}
.dropdown-content {
display: none;
position: absolute;
background-color: #f1f1f1;
min-width: 160px;
overflow: auto;
box-shadow: 0px 8px 16px 0px rgba(0,0,0,0.2);
z-index: 1;
}
.dropdown-content a {
color: black;
padding: 12px 16px;
text-decoration: none;
display: block;
}
.dropdown a:hover {background-color: #ddd;}
.show {display: block; }
<div class="dropdown">
<button class="dropbtn">Dropdown 1</button>
<div class="dropdown-content">
<a href="#home">Home 1</a>
<a href="#about">About 1</a>
<a href="#contact">Contact 1</a>
</div>
</div>
<div class="dropdown">
<button class="dropbtn">Dropdown 2</button>
<div class="dropdown-content">
<a href="#home">Home 2</a>
<a href="#about">About 2</a>
<a href="#contact">Contact 2</a>
</div>
</div>
<div class="dropdown">
<button class="dropbtn">Dropdown 3</button>
<div class="dropdown-content">
<a href="#home">Home 3</a>
<a href="#about">About 3</a>
<a href="#contact">Contact 3</a>
</div>
</div>