我有2个型号:
class City(models.Model):
name = models.CharField(max_length=50)
slug = models.SlugField(max_length=50)
class CityNews(models.Model):
title = models.CharField(max_length=100)
slug = models.SlugField(max_length=100)
add_date = models.DateTimeField(auto_now=False, auto_now_add=True, editable=False)
content = models.TextField()
city = models.ForeignKey(City)
我的每个用户都与1个城市相关联。我希望他只将新闻添加到他所连接的城市。但是,superadmin必须有可能向每个城市添加新闻。 如何更改CityNews中的“城市”字段,它们只显示用户所连接的城市?我可以编写自定义ModelForm但是如何在那里检查user_city并更改其查询集?
答案 0 :(得分:9)
这样做的一个显而易见的方法是在ModelAdmin上使用formfield_for_foreignkey()方法。
所以如果你的models.py看起来像这样:
from django.db import models
from django.contrib.auth.models import User
class City(models.Model):
name = models.CharField(max_length=50)
def __unicode__(self):
return self.name
class CityNews(models.Model):
added_by = models.ForeignKey(User)
city = models.ForeignKey(City)
title = models.CharField(max_length=100)
content = models.TextField()
class UserExtra(models.Model):
user = models.ForeignKey(User)
city = models.ForeignKey(City)
然后你的admin.py看起来像这样:
from django.contrib import admin
from formtesting.models import City, CityNews, UserExtra
from django.forms.models import ModelChoiceField
from django.contrib.auth.models import User
class CityAdmin(admin.ModelAdmin):
pass
admin.site.register(City, CityAdmin)
class CityNewsAdmin(admin.ModelAdmin):
def formfield_for_foreignkey(self, db_field, request, **kwargs):
if db_field.name == "city":
if request.user.is_superuser:
queryset = City.objects.all()
else:
queryset = City.objects.filter(userextra__user=request.user)
return ModelChoiceField(queryset, initial=request.user)
elif db_field.name == "added_by":
if request.user.is_superuser:
queryset = User.objects.all()
else:
queryset = User.objects.filter(id=request.user.id)
return ModelChoiceField(queryset, initial=request.user)
else:
return super(CityNewsAdmin, self).formfield_for_foreignkey(db_field,
request, **kwargs)
admin.site.register(CityNews, CityNewsAdmin)
class UserExtraAdmin(admin.ModelAdmin):
pass
admin.site.register(UserExtra, UserExtraAdmin)