Question

如何将消息发送到特定频道？为什么会出现此错误？我的ChannelID是正确的

代码：

from discord.ext import commands


client = commands.Bot(command_prefix='!')
channel = client.get_channel('693503765059338280')



@client.event
async def on_ready():
    print('Bot wurde gestartet: ' + client.user.name)
#wts        
@client.command()
async def test(ctx,name_schuh,preis,festpreis):
    await channel.send(discord.Object(id='693503765059338280'),"Name:" + name_schuh +"\n Preis: " + preis +"\n Festpreis: " + festpreis)

错误：

raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: AttributeError: 'NoneType' object has no attribute 'send'

Answer 1

发生错误的原因是因为在连接机器人之前调用了channel = client.get_channel()，这意味着它将始终返回None，因为它看不到任何通道（未连接）。

将其移动到命令函数内部，使其在调用命令时获得channel对象。

还要注意，从1.0版开始，snowflakes are now int type instead of str type。这意味着您需要使用client.get_channel(693503765059338280)而不是client.get_channel('693503765059338280')。

from discord.ext import commands


client = commands.Bot(command_prefix='!')


@client.event
async def on_ready():
    print('Bot wurde gestartet: ' + client.user.name)

@client.command()
async def test(ctx,name_schuh,preis,festpreis):
    channel = client.get_channel(693503765059338280)
    await channel.send("Name:" + name_schuh +"\n Preis: " + preis +"\n Festpreis: " + festpreis)

client.run('token')

Answer 2

client和channel不在范围内。您可以使用global关键字进行肮脏的入侵：

from discord.ext import commands

client = commands.Bot(command_prefix='!')
channel = client.get_channel(693503765059338280)

@client.event
async def on_ready():
    global client
    print('Bot wurde gestartet: ' + client.user.name)

#wts        
@client.command()
async def test(ctx,name_schuh,preis,festpreis):
    global client
    global channel
    await channel.send(discord.Object(id=693503765059338280),"Name:" + name_schuh +"\n Preis: " + preis +"\n Festpreis: " + festpreis)

但是更好的选择是保存实例的处理程序类。

如何将消息发送到特定频道？不和谐/ Python

2 个答案: